3 years ago

Which expressions are equivalent to 4(x+1) + 7(x+3)? Select two answers.

Mathematics

1 answer:

Natalija [7]3 years ago

7 0

Answer:

9(x+3) + 2(x+3) or 10(x+2) +(x+5)

Step-by-step explanation:

First you want to distribute the equation.

4(x+1) + 7(x+3) multiplied out is

4x + 4 + 7x + 21

Now we add like terms so it comes out to

11x + 25

Two expressions that can come out to equal 11x + 25 is. 9(x+3) + 2(x+3) or 10(x+2) +(x+5)

You might be interested in

Write 6×10 to the power of 4 in standard form! Please include an explanation! Thanks!

lidiya [134]

Answer:

60,000

Step-by-step explanation:

Evalute

6 x 10*4

6 x 10,000

60,000 is the standard form :)

3 0

2 years ago

Read 2 more answers

What is the vertex of the graph of the function below? y = x2 + 6x + 5

Aleksandr-060686 [28]

Answer:

(-3,-4)

If you have a chart with the coordinates in it, it will be in the middle of alike coordinates.

7 0

3 years ago

5pts and whoever has the correct answer gets brainliest

USPshnik [31]

Answer:

Step-by-step explanation:

8 0

1 year ago

In 2010, there were 311 middle schools in Virginia. In 2016, there were 306. By what percent did the number of middle schools in

Nataly_w [17]

Answer:1.6%

Step-by-step explanation: no of students in 2010=311

no of students in 2016=306

difference=311-306

%decrease=5/311 x 100

3 0

2 years ago

Consider the sequence: 1536,768, 384, 192,96, --- Determine the 11th term of the sequence.

Naya [18.7K]

Answer:

1.5

Step-by-step explanation:

Note there is a common ratio between consecutive terms, that is

768 ÷ 1536 = 0.5

384 ÷ 768 = 0.5

192 ÷ 384 = 0.5

96 ÷ 192 = 0.5

This indicates that the terms form a geometric sequence with

$a_{n}$ = a $(r)^{n-1}$

where a is the first term and r the common ratio

Here a = 1536 and r = 0.5, thus

$a_{11}$ = 1536 × $(0.5)^{10}$ = 1.5

7 0

3 years ago

Read 2 more answers