Answer:
solution is 9a^16
Step-by-step explanation:
(6)^2= 36
(a^5)^2= a^25
36a^25/(9a^9)
(36/9)= 4
(a^25)/(a^9)= a^(25-9)= a^16
1. Answer = About 1451.42 m³
- First, we need to find the volume of the cube:
- Formula: πr²h
- Volume = π * 3² * 50 = 1413.72 m³
- Second, we need to find the volume of the cone:
- Formula: (πr²h)/3
- Volume = π * 3² * 4 = 37.69 m³
- Third, we need to add these two volumes to find the total volume of the figure.
- 1413.72 m³ + 37.69 m³ = 1451.42 m³.
2. Answer <em>= </em>960 m³
- Formula: (1/2(b*l)) * 20
- First, we need to find the area of the base (1/2 * b* l).
- 1/2 * 8 * 12 = 48.
- Second, we need to multiply the area of the base by the height to get the volume.
- B * h = 48 * 20 = 960 m³.
Answer:
Check the solution below
Step-by-step explanation:
2) Given the equation
x +y =5... 1 and
x-y =3 ... 2
Add both equations
x+x = 5+3
2x = 8
x = 8/2
x = 4
Substitute x = 4 into 1:
From 1: x+y = 5
4+y= 5
y = 5-4
y = 1
3) Given
x+3y =15 ... 1
2x+7y=19 .... 2
From 2: x = 15-3y
Substitute into 2
2(15-3y)+7y = 19
30-6y+7y = 19
30+y = 19
y = 19-30
y = -11
Substitute y=-11 into x = 15-3y
x =15-3(-11)
x = 15+33
x = 48
The solution set is (48, -11)
4) given
x/2 +y/3 =0 and x+2y=1
From 1
(3x+2y)/6 = 0
3x+2y = 0.. 3
x+2y= 1... 4
From 4: x = 1-2y
Substutute
3(1-2y) +2y = 0
3-6y+2y = 0
3 -4y = 0
4y = 3
y = 3/4
Since x = 1-2y
x = 1-2(3/4)
x = 1-3/2
x= -1/2
The solution set is (-1/2, 3/4)
5) Given
5.x=1/2 and y =x +1 then solution is
We already know the vkue of x
Get y
y= x+1
y = 1/2 + 1
y = 3/2
Hence the solution set is (1/2, 3/2)
6) Given
3x +y =5 and x -3y =5
From 3; x = 5+3y
Substitute into 1;
3(5+3y)+y = 5
15+9y+y = 5
10y = 5-15
10y =-10
y = -1
Get x;
x = 5+3y
x = 5+3(-1)
x = 5-3
x = 2
Hence two solution set is (2,-1)
Answer:
159cm
Step-by-step explanation:
Sum of all sides of triangles is 180
so, 15+6=21
then 180-21=159
The first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132
<h3>Highest common factors</h3>
The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.
According to the question, we are to find two numbers between 100 and
150 that have a HCF of 22.
In order to do that we will<u> multiply 22 by the values 5 and 6</u>
First number = 22 * 5 = 10
Second number = 22 * 6 = 132
Hence the first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132
Learn more on HCF here; brainly.com/question/21504246
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