Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
4y+2x=14 ==> multiply this 1st equation by (-1) => -4y-2x=-14
Now add it up to the 2nd equation
-4y-2x=-14
2y+2x=10
-------------- And now add them up
-2y +0x=-4
==> -2y=-4==> 2y = 4 & y=2
Last step: plug y into any equation & you will find x=3
Answer:
Town B will eventually overtake Town A
in 1990 Town B will have a larger population
Step-by-step explanation:
To work out how big town A will be in 1990 you need to do 200 + (200x40) because you add 40 years worth of increased population onto the starting population
To work out how big town B will be in 1990 you need to use the equation 200 X 1.1^40 because to work out plus 10 percent you need to do 1.1 and do it to the power of 40 for how many years
in 1990 town a will have a population of 8200 and town B will have a population of 9051.85
Step-by-step explanation:
Use formula for cube volume:
V=a³
Then add informations you already have and you are done.
V=0,5³
V=0,125 m³