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3 years ago

Find the whole. 175% of ___is 42. Explain your method.

Mathematics

2 answers:

Rasek [7]3 years ago

8 0

Answer:

24

Step-by-step explanation:

Hi there !

175% ............. 42

100% ..................x

x = 100*42/175 = 4200/175 = 24

Good luck !

xxTIMURxx [149]3 years ago

6 0

Answer:

Step-by-step explanation:

175%=1.75

42/1.75=24

hope this helps

let me know

(Also i would love to get brainliest)

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What is the area of the shaded sector? (Round to the nearest tenth) 10 38

masya89 [10]

Answer:

33.1

Step-by-step explanation:

First you need to find the area of the circle. The radius is 10 which means that the area is 314. Since a circle has 360 degrees, and the shaded area is 38 degrees, you need to divide 314 by 360 which is 0.87. Then multiply by 38 because the shaded sector is 38. 0.87 x 38 = 33.1.

That is the answer.

5 0

2 years ago

Ellie borrows money at a year simple rate of 6 1/2% after 4 years ellie owes 39 interest

kupik [55]

Answer: Ellie borrowed $150.

Step-by-step explanation:

I = PRT

39 = P x 0.065 x 4

39 = P x 0.26

Divide both sides by 0.26

150 = P

6 0

2 years ago

Round 939,515 to the nearest ten

Radda [10]

Answer:

939,520 would be the answer. You're rounding the 15 part up to the next ten which would be 20, making the answer 939,520.

6 0

3 years ago

Read 2 more answers

On a number line 8.63 would be located where

Oksanka [162]

Answer:

It would be slightly higher than 8.5 and lower than 9.

Step-by-step explanation:

8.6 is bigger than 8.5, but it's smaller than 9, so you would place it in between the two but closer to the 8.5 mark.

4 0

3 years ago

. Given that O is the centre of the following circle, find the values of the unknowns.

alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

$a^{2} + 5^{2} = 13^{2}$

$a^{2} + 25 = 169$

$a^{2} = 169 - 25$

$a^{2} = 144$

$\sqrt{a^{2}}=\sqrt{144}$

$a = 12$

Now to find the value of 'b', i will use law of cosine,

$c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }$

$12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta = 0.3846\\\beta = cos^{-1}(0.3846)\\\beta = 67.38$

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

If u need any help feel free to ask

3 0

3 years ago