Hi there
The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 100
R interest rate 0.02
K compounded monthly 12
T time?
We need to solve for t
T=[log (A/p)÷log (1+r/k)]÷k
T=(log(3,000÷100)÷log(1+0.02÷12))÷12
T=170.202 years
So it's a
Hope it helps
Answer: 7.3
Step-by-step explanation:
Do the parentheses first!
4-7= -3
Then, multiply -3 by 2
-3×2= -6
Next,
-6-6.7= -12.7
Then, add -12.7 to 20
-12.7+20=7.3
Your answer is 7.3
Answer:
x^3-6x^2-4x-8
Step-by-step explanation:
First you would multiply (x-2) by itself (x-2) to get
x^2-2x-2x+4
then you would combine like terms
x^2-4x+4
Then you would multiply that by x-2
(x^2-4x+4)(x-2)
x^3-2x^2-4x^2-8x+4x-8
then you combine like terms
x^3-6x^2-4x-8
3^3. if you're simplifying then you keep the base the smae but add the exponents since you are "multiplying" the bases
