sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
<u>Step-by-step explanation:</u>
We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)
Given sequence is an AP with following parameters as :
So , Let's calculate how many terms are there as :
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Sum of an AP is :
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Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
The slope of the line is 2
Option B. 2 because 2-8
------- = -3
2
Please use * to denote mult. here, not "x." "x" is your variable and cannnot also be a symbol for mult.
f(x)g(x) = 3x^3 - 5x^2.
Now let x = 3:
(f*g)(3) = 3(3)^3 - 5(3)^2 = 81-45 = 36 (answer)