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3 years ago

There are nine players on a baseball team. How many different batting lineups are possible

Mathematics

2 answers:

jolli1 [7]3 years ago

7 0

Answer:

362,880

Step-by-step explanation:

9*8*7*6*5*4*3*2*1=362,880. You multiply the number of players, but subtract one each time.

ipn [44]3 years ago

6 0

Answer: 362,800

Step-by-step explanation: To determine how many different batting orders are possible for a 9-player softball team, let's start by drawing 9 blanks to represent the 9 spots in the order.

We know that 9 different players can fill the first spot in the order. However, once the first spot is filled, there are only 8 players left to fill the second spot and once the second spot is filled, there are only 7 players left to fill the third spot and so on.

Therefore, based on the counting principal, we have 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 ways for all 9 spots to be filled which simplifies to 362,880.

Therefore, there are 362,880 different batting orders for a 9-player softball team.

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3 years ago

Read 2 more answers

The sum of three consecutive odd integers is -75. What is the smallest number

pashok25 [27]

Answer:

-27

Step-by-step explanation:

First, let's call the smallest number: n

Then, the next two consecutive odd numbers would be:

n+2 and n+4 (this is because it's only odd numbers so we add 2)

We know the sum of these is −75 so we can write this equation and solve for n:

n + (n + 2) + (n + 4) = -75

n + n + 2 + n + 4 = -75

n + n + n + 2 + 4 = -75

n + n + n + 6 = -75

1n + 1n + 1n + 6 = -75

3n + 6 = -75 Subtract 6 from each side, which cancels the 6 on the left.

3n + 6 - 6 = -75 - 6

3n = -75 - 6

3n = -81 Divide each side by 3

3n/3 = -81/3

n = -81/3

n = -27

n + 2 = -27 + 2 = -25

n + 4 = -27 + 4 = -23

The 3 consecutive odd integers would be:

-27, -25, -23

Let's check our work:

-27 + -25 + -23 = -75 We are correct!

The smallest number is -27

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Answer h:

Step-by-step explanation:

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