There are nine players on a baseball team. How many different batting lineups are possible
2 answers:
Answer: 362,800
Step-by-step explanation: To determine how many different batting orders are possible for a 9-player softball team, let's start by drawing 9 blanks to represent the 9 spots in the order.
We know that 9 different players can fill the first spot in the order. However, once the first spot is filled, there are only 8 players left to fill the second spot and once the second spot is filled, there are only 7 players left to fill the third spot and so on.
Therefore, based on the counting principal, we have 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 ways for all 9 spots to be filled which simplifies to 362,880.
Therefore, there are 362,880 different batting orders for a 9-player softball team.
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Answer:
165 different teams of 3 students can be formed for competitions
Step-by-step explanation:
Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:
- Not all items fit
- No matter the order
- Elements are not repeated
That is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.
To calculate the number of combinations, the following expression is applied:
It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.
In this case:
- n: 3
- m: 11
Replacing:
Solving:
being:
- 3!=3*2*1=6
- 8!=8*7*6*5*4*3*2*1=40,320
- 11!=39,916,800
So:
C= 165
<u><em>165 different teams of 3 students can be formed for competitions</em></u>