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inessss [21]
3 years ago
8

Expand and simplify (x+2) (x+3) (x+4)

Mathematics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

3x+9

Step-by-step explanation:

1(x+2) +1(x+3) +1(x+4)

<em>x+2+x+3+x+4</em>

<em>x+x+x+2+3+4</em>

<u><em>3x+9</em></u>

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Find the product -7(-a2)(-b3)
vlada-n [284]
-7(-a^2)(-b^3)=\boxed{-7a^2b^3}
7 0
3 years ago
Angle c is inscribed in circle O. AB is a diameter of circle O. what is the radius of circle.​
Llana [10]

Answer:

The value of radius is 7.5 units

Step-by-step explanation:

Given that a line that pass through the origin and form a triangle is a right-angle triangle. So in order to find the diameter/hypotenuse, you have to use Pythogaras Theorem :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Let a = 12 units,

Let b = 9 units,

Let c = hypo.,

{hypo.}^{2}  =  {12}^{2}  +  {9}^{2}

{hypo.}^{2}  = 225

hypo. =  \sqrt{225}

hypo. = 15 \:  \: units

We have found out that the hypotenuse of the triangle is the diameter of circle. So in order to find radius, you have to divide it by 2 :

radius = diameter \div 2

radius = 15 \div 2

radius = 7.5 \:  \: units

6 0
3 years ago
Heyyyyy! Need Help with this! I will give brainliest to correct answer!! &lt;3
Alex787 [66]

Answer:

The answer is 1/8 pints left

Step-by-step explanation:

If you had 3/4 pints already and you poured 5/8 pints into your glass, you would only have 1/8 pints left. First you need to make them both have the same denominator (8) to do that you need to multiply 3/4(2)=6/8. 6/8-5/8=1/8 pints left.

5 0
3 years ago
Explain how you can identify a non proportional relationship?
noname [10]
Simply simplify the ratios/fractions into their simplest fraction form and divide the numerator by the denominator. If they are equal, they are in fact proportions, if not, they aren't
5 0
4 years ago
A taxi driver had 29 fares to and from the airport last Monday. The price for a ride to the airport is $4.50, and the price for
Serhud [2]

Answer:(12,17)

Step-by-step explanation:

X + y= 29

4.50x + 7y=173

Solve by elimination.

5 0
3 years ago
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