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Nadya [2.5K]
3 years ago
15

You are considering two independent projects that have differing requirements. Project A has a required return of 12 percent com

pared to Project B’s required return of 13.5 percent. Project A costs $75,000 and has cash flows of $21,000, $49,000, and $12,000 for Years 1 to 3, respectively. Project B has an initial cost of $70,000 and cash flows of $15,000, $18,000, and $41,000 for Years 1 to 3, respectively. Given this information, you should:
1. accept both Project A and Project B.
2. accept Project A and reject Project B.
3. accept Project B and reject Project A.
4. reject both Project A and Project B.
5. accept whichever one you want but not both.
Business
1 answer:
finlep [7]3 years ago
4 0

Answer:

4. reject both Project A and Project B.

their NPV are negative so are not profitable.

Explanation:

We have to calculate the present value of the projects at their return rate

<u>Project A</u>

Present value of the cash flow - investment = net present value

\frac{21,000}{(1.12)^{1} } = PV

\frac{49,000}{(1.12)^{2} } = PV

\frac{12,000}{(1.12)^{3} } = PV

-75,000 + PV 21,000 + PV 49,000 + PV 12,000

-75,000 + 18,750 + 39062.5 + 8,541.36 = -8646.14

<u>Project B</u>

Present value of the cash flow - investment = net present value

-70,000 + PV 15,000 + PV 18,000 + PV 41,000

\frac{15,000}{(1.135)^{1} } = PV

\frac{18,000}{(1.135)^{2} } = PV

\frac{41,000}{(1.135)^{3} } = PV

-70,000 + 13215.86 + 13972.71 + 28041.18 = -14770.25

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Blue Ridge Bank has a PM of 12 percent, an interest income to total assets ratio of 6.00 percent, and a noninterest income to as
lakkis [162]

Answer:

8.10 Percent

Explanation:

= 0.12 * (6% + 1.50%) * 9

= 8.10%

5 0
3 years ago
How much will a company's net operating income change if it undertakes an advertising campaign given the following data: Cost of
Olegator [25]

Answer:

Increase in net operating is $9,800

Explanation:

<u>Computation table</u>

Increase in sales                         $60,000

<u>Less:Variable expense (42%)    $25,200</u>

<u>Increase in contribution             $34,800</u>

<u>Less:Cost of advertising            $ 25,000 </u>

<u>Increase in net operating          $9,800</u>

<u />

5 0
3 years ago
The purchase price and all costs to bring an asset to its desired condition and location for use should be ________.
Nana76 [90]

Answer:

b. capitalized

Explanation:

The purchase price and all costs to bring an asset to its desired condition and location for use should be capitalized.

3 0
3 years ago
Suppose you invest $2500 each year in a savings account that earns 12% per year. How much will be in the account in 10 years?
iVinArrow [24]

Answer:

Final Value= $43,871.84

Explanation:

Giving the following information:

Suppose you invest $2500 each year in a savings account that earns 12% per year.

Number of years= 10

To calculate the final value we need to use the following formula:

FV= {A*[(1+i)^n-1]}/i

A= annual deposit= 2,500

i= 0.12

n=10

FV= {2,500*[(1.12^10)-1]}/0.12= $43,871.84

4 0
3 years ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
3 years ago
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