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lisov135 [29]
3 years ago
13

0.5w + 1.7w -0.5 PLEASE HELP ME

Mathematics
2 answers:
ANTONII [103]3 years ago
7 0

Answer:

2.2 w  −  0.5

Step-by-step explanation:

AnnZ [28]3 years ago
6 0
If you’re simplifying then you’re answer is 2.2w-0.5 combine like terms would be the same answer !
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The cost of a sweatshirt is 175% the cost of a T-shirt. A T-shirt costs $13.
Molodets [167]

Answer:

$68.25

Step-by-step explanation:

1. First, to find the cost of one sweatshirt, we multiply 175 by 13, and then divide by 100.

  • 175 * 13 = 2275
  • 2275/100=22.75

2. Now, we know that one sweatshirt costs $22.75. To find the cost of three sweatshirts, we multiply 22.75 by 3.

  • 22.75 * 3
  • 68.25

Therefore, the cost of 3 sweatshirts is $68.25.

8 0
2 years ago
Which of the functions have a range of all real numbers? Check all that apply. A. y = sec x B. y = csc x C. y = tan x D. y = cot
Nastasia [14]

Answer:

Option C and D that is y= tan x and y= cot x

Step-by-step explanation:

The range is the values of y means the values that y can take in a function:

So, range of tan x and cot x are all real numbers.

Period of  tan x is \pi

Period of cot x is \pi

Option A and B that is secx and csc x are discarded  

4 0
4 years ago
Read 2 more answers
April sold 75 tickets to a school play and collected a total of $495. If adult cost $8 each and child tickets cost $5 each, how
Sveta_85 [38]
April Sold 3 children tickets and 60 adult tickets.
Correct me if I'm wrong. ;-;
7 0
3 years ago
Read 2 more answers
Students in a class are asked to stand in ascending order according to their heights for the annual class photograph. Determine
horrorfan [7]

Answer:

The function in Python is as follows:

def heightChecker(heights):

   expected = []

   count = 0

   for i in range(len(heights)):

       expected.append(heights[i])      

   expected.sort()

   for i in range(len(heights)):

       if expected[i] != heights[i]:

           count+=1  

   return count

Step-by-step explanation:

Required

Function to return the number of out of position students

<em>See comment for complete question</em>

This defines the function. It receives the heights as a parameter, from the main

def heightChecker(heights):

This initializes a list, (expected list)

   expected = []

This initializes the count of out of position students

   count = 0

This iterates through the original list

   for i in range(len(heights)):

The list item is then appended to the expected list

       expected.append(heights[i])      

This sorts the expected list in ascending order

   expected.sort()

This iterates through the original and the expected lists

   for i in range(len(heights)):

If list elements at the same index are not the same, count is incremented by 1

<em>        if expected[i] != heights[i]: </em>

<em>            count+=1  </em>

This returns count

   return count

4 0
3 years ago
Solve each equation.SHOW work plz
Studentka2010 [4]
3 \frac{1}{2} r = 28 \\  \frac{7}{2} r = 28 \\  \frac{ \frac{7}{2} }{ \frac{7}{2} } r =  \frac{28}{ \frac{7}{2} }  \\ r =  \frac{ \frac{56}{2} }{ \frac{7}{2} }  \\ r= \frac{56}{7}

1 \frac{1}{2} c =6 \\  \frac{3}{2} c= \frac{12}{2}  \\  \frac{ \frac{3}{2} }{ \frac{3}{2} } c= \frac{ \frac{12}{2} }{ \frac{3}{2} }  \\ c= \frac{ \frac{12}{2} }{ \frac{3}{2} } = \frac{12}{3} =4 \\ c=4

7 0
3 years ago
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