1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisabon 2012 [21]
3 years ago
14

A hydrated sample of cobalt II chloride has a molar mass of 309.99 g/mol. What is the mole ratio between cobalt II chloride and

water?
Chemistry
2 answers:
VLD [36.1K]3 years ago
4 0

Explanation:

Let there be 1 mole of CoCl2.

Mass of CoCl2 = 1mol * (129.839g/mol) = 129.839g

Mass of H2O = 309.99g - 129.839g = 180.151g

Moles of H2O = 180.151g / (18g/mol) = 10mol

Hence the mole ratio of CoCl2 to H2O is 1 : 10.

earnstyle [38]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 1 \ mole \ CoCl_2 \ to \ 10 \ mole \ H_2O}}

Explanation:

First, identify the formula of cobalt II chloride: CoCl₂

Next, find the molar mass of CoCl₂. Identify the individual element's mass.

  • Cobalt (Co): 58.93319 g/mol
  • Chlorine (Cl): 35.45 g/mol

Since there is a subscript of 2 after the Cl, we must multiply the molar mass of chlorine by 2

  • CoCl₂: (58.93319 g/mol) + (2* 35.45 g/mol) = (58.93319 g/mol)+(70.9 g/mol)
  • 129.83319 g/mol

Assuming the sample is 1 mole, we can subtract the mass we just found from the hydrate sample's mass. This is the mass of the water.

  • 309.99 g - 129.83319 g= 180.15681 g

Now, we need to find the number of moles of water. Begin by finding the molar mass of water: H₂O

  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 15.999 g/mol

Since there is a subscript of 2 after the H, we must multiply the molar mass of hydrogen by 2.

  • H₂O: (1.008 g/mol *2)+ 15.999 g/mol = (2.016 g/mol)+(15.999 g/mol)=18.006 g/mol

Finally, divide the mass of the water by the molar mass of water.

  • 180.15681 g / 18.006 g/mol

Note that the grams or g will cancel.

  • 180.15681 / 18.006 mol = 10.00537654 mol

This is roughly 10, so we can round to 10.

  • ≈ 10 mol H₂O

So, the mole ratio is 1 mole CoCl₂ to 10 mole H₂O

You might be interested in
If a 100-N net force acts on a 50kg car what will the acceleration of the car be
aliina [53]
The acceleration is equal to force divided by mass which would be 100 / 50 which is 2 m/s2
6 0
3 years ago
. A compound contains only C, H, N, and O. It contains 37.0 % C and 42.5% O (both by mass), and there are 2 O atoms for every 1
jasenka [17]

Answer:

C₂₁H₁₅N₉O₁₈

Explanation:

Molecular formula is the ratio of atoms that are present in 1 molecule of the compound. We need to find moles of all atoms to find this ratio.

In a basis of 100, moles of C and O are:

<em>Moles C:</em>

37.0 * (1mol / 12g) = 3.083 moles C

<em>Moles O: </em>

42.5g * (1mol / 16) = 2.656 moles O

Now, to find moles of H, we need determine moles of H2O produced:

0.0310g H2O * (1mol / 18g) = 1.72x10⁻³ moles H2O * 2 = 3.44x10⁻³ moles H

These moles were produced when 0.157g of the compound react. In a basis of 100g:

3.44x10⁻³ moles H * (100g / 0.157g) = 2.194 moles H

In the same way, moles of N are:

0.0230g NH3 * (1mol / 17g) = 1.35x10⁻³ moles H2O

These moles were produced when 0.103g of the compound react. In a basis of 100g:

1.35x10⁻³ moles H * (100g / 0.103g) = 1.313 moles N

Empirical formula is (The simplest whole number ratio of atoms presents in a molecule). Dividing in the low number of moles (Moles N):

C: 3.083 moles C / 1.313 moles N = 2.3

O: 2.656 moles O / 1.313 moles N = 2.0

N: 1.313 moles N / 1.313 moles N = 1

H: 2.194 moles H / 1.313 moles N = 1.67

This ratio times 3 (To have the whole number ratio):

C: 7

O: 6

N: 3

H: 5

The empirical formula is:

C₇H₅N₃O₆

And weighs:

C: 7*(12g/mol)= 84

H: 5 * (1g/mol) = 5

N: 3 * (14g/mol) = 42

O: 6* (16g/mol) = 96

227g/mol

As the molecular mass of the compound is 681g/mol:

681 / 227 = 3

The empirical formula times 3 is the molecular formula, that is:

C₇H₅N₃O₆ × 3

<h3>C₂₁H₁₅N₉O₁₈</h3>

4 0
3 years ago
The difference between 24.31 and 18.62
coldgirl [10]

24.31-18.62=5.69

The answer is 5.69

3 0
4 years ago
Compare Boyle's law, Charles's law, and Avogadro's law. a. What remains constant in each law? b. What are the variables in each
zavuch27 [327]

Answer:

a)

In Boyle's Law, the variable that remains constant is the absolute temperature of the gas.

In Charle's Law, the variable that remains constant is the pressure of the gas.

In Avogadro's Law, the variables that remain constant are pressure and temperature of the gas.

b)

In Boyle's Law, the variables involved are pressure and volume: the law states that for a fixed mass of ideal gas at constant temperature, the pressure of the gas is inversely proportional to the volume:

p\propto \frac{1}{V}

where p is the pressure of the gas and V the volume.

In Charle's Law, the variables involved are volume and temperature: the law states that for a  fixed mass of ideal gas at constant pressure, the volume of the gas is directly proportional to the temperature:

V\propto T

where V is the volume of the gas and T the temperature.

In Avogadro's Law, the variables involved are the volume and the number of moles: the law states that for an ideal gas kept at constant pressure and temperature, the volume of the gas is directly proportional to the number of moles:

V\propto n

Where V is the volume of the gas and n the number of moles.

c)

See the graphs of the three Laws in attachment:

- First graph: Boyle's Law, which shows that the pressure of the gas is inversely proportional to the volume

- Second Graph: Charle's Law, which shows that the volume of the gas is directly proportional to the absolute temperature

- Third graph: Avogadro's Law, which shows that the volume of the gas is directly proportional to the number of moles of the gas

d)

Here we want to re-write the three laws by making V the subject.

For Boyle's law, we get:

V\propto \frac{1}{p}

For Charle's Law, we get:

V\propto T

For Avogadro's Law, we get:

V\propto n

Therefore, we see that the two laws that show a direct proportionality are Charle's Law and Avogadro's Law, while Boyle's Law shows an inverse proportionality between the two variables.

8 0
4 years ago
Which of the following gases would have the greatest kinetic energy at 300 K?
tekilochka [14]

Answer:

D. All of them would have the same kinetic energy

Explanation:

The expression for the kinetic energy of the gas is:-

K.E.=\frac{3}{2}\times K\times T

k is Boltzmann's constant = 1.38\times 10^{-23}\ J/K

T is the temperature

<u>Since, kinetic energy depends only on the temperature. Thus, at same temperature, at 300 K, all the gases which are N_2,\ NH_3\ and\ Ar will posses same value of kinetic energy.</u>

4 0
3 years ago
Other questions:
  • What is the chemical formula for nickel (ii) hypochlorite?
    15·1 answer
  • How many milliliters of 0.50 M KOH are needed
    9·1 answer
  • 1. a.) Calculate the wavelength of light which has a frequency of 5.25 x 10 14 Hz.
    8·1 answer
  • If “A” is a halogen in the formal equation, A + BC -&gt; __, what letter would it be replacing?
    5·1 answer
  • Which change will always result in an increase in the gravitational force between two objects?
    15·1 answer
  • Chemistry hw due in 2 hours... HELP!!!
    5·1 answer
  • ! !!
    14·2 answers
  • Over time, what color will all the fish be because of natural selection?
    8·2 answers
  • Which would have the highest first ionization energy?
    14·2 answers
  • Help! How is this incorrect?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!