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3 years ago

What is relation between liquid pressure and depth

1 answer:

4 0

<h2>Liquid pressure and depth have a <u>directly proportional </u> <u>relationship</u>. This is due to the greater column of water that pushes down on an object submersed. Conversely, as objects are lifted, and depth decreases, pressure is reduced.</h2>

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What is the total magnification for each lens setting on a microscope with 15x oculars and 4x, 10x, 45x, and 97x objectives lens

KengaRu [80]

Answer:

M = 60x

M = 150x

M = 675x

M = 1455 x

Explanation:

In a microscope the total magnification is found by multiplying the magnification of the ocular (eye piece) and objective lens.

$m_e$ =Ocular magnification = 15x

$m_o$ =Objective magnification = 4x

Total magnification

$M=m_e\times m_o\\\Rightarrow M=15\times 4\\\Rightarrow M=60x$

M = 60x

$M=m_e\times m_o\\\Rightarrow M=15\times 10\\\Rightarrow M=150x$

M = 150x

$M=m_e\times m_o\\\Rightarrow M=15\times 45\\\Rightarrow M=675x$

M = 675x

$M=m_e\times m_o\\\Rightarrow M=15\times 97\\\Rightarrow M=1455x$

M = 1455 x

7 0

3 years ago

What advantage is there in using a set of helmholtz coils over just a single small magnet?

denis23 [38]

Two parallel coils separated by a distance equal to the radius of the coils are known as Helmholtz coils. They are frequently used because they generate a magnetic field that is uniform over an appreciable region about its midpoint. <span>
</span>

7 0

3 years ago

What is the definition of physical weathering?

jeyben [28]

Answer rocks, soil and minerals being slowly broken down or broken apart by the Earth's environment such as pressure, temperature, water and ice

5 0

4 years ago

Give 3 examples of momentum used in everyday life.

Arte-miy333 [17]

Answer:

waking up,eat,sleep

Explanation:

notice how i didn't say math :)

8 0

3 years ago

Insert

nordsb [41]

A) 320 count/min

B) 40 count/min

C) 80 count/min, 11400 years

Explanation:

The activity of a radioactive sample is the number of decays per second in the sample.

The activity of a sample is therefore directly proportional to the number of nuclei in the sample:

$A\propto N$

where A is the activity and N the number of nuclei.

As a consequence, since the number of nuclei is proportional to the mass of the sample, the activity is also directly proportional to the mass of the sample:

$A\propto m$

where m is the mass of the sample.

In this problem:

- When the mass is $m_1 = 1 g$ , the activity is $A_1=16 count/min$

- When the mass is $m_2=20 g$ , the activity is $A_2$

So we can find A2 by using the rule of three:

$\frac{A_1}{m_1}=\frac{A_2}{m_2}\\A_2=A_1 \frac{m_2}{m_1}=(16)\frac{20}{1}=320 count/min$

The equation describing the activity of a radioactive sample as a function of time is:

$A(t)= A_0 e^{-\lambda t}$ (1)

where

$A_0$ is the initial activity at time t = 0

t is the time

$\lambda$ is the decay constant, which gives the probability of decay

The decay constant can be found using the equation

$\lambda = \frac{ln2}{t_{1/2}}$

where $t_{1/2}$ is the half-life, which is the amount of time it takes for the radioactive sample to halve its activity.

In this problem, carbon-14 has half-life of

$t_{1/2}=5700 y$

So its decay constant is

$\lambda=\frac{ln2}{5700}=1.22\cdot 10^{-4} y^{-1}$

We also know that the tree died

t = 17,100 years ago

and that the initial activity was

$A_0 = 320 count/min$ (value calculated in part A, corresponding to a mass of 20 g)

So, substituting into eq(1), we find the new activity:

$A(17,100) = (320)e^{-(1.22\cdot 10^{-4})(17,100)}=40 count/min$

We know that a sample of living wood has an activity of

$A=16 count/min$ per 1 g of mass.

Here we have 5 g of mass, therefore the activity of the sample when it was living was:

$A_0 = A\cdot 5 = (16)(5)=80 count/min$

Moreover, here we have a sample of 5 g, with current activity of $A=20 count/min$ : it means that its activity per gram of mass is

$A'=\frac{20}{5}=4 count/min$

We know that the activity halves after every half-life: Here the activity has became 1/4 of the original value, this means that 2 half-lives have passed, because:

- After 1 half-life, the activity drops from 16 count/min to 8 count/min

- After 2 half-lives, the activity dropd to 4 count/min

So the age of the wood is equal to 2 half-lives, which is:

$t=2t_{1/2}=2(5700)=11,400 y$

3 0

4 years ago