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lukranit [14]
3 years ago
9

The vector quantity that defines the distance and direction between two positions. It is a change in your position.

Physics
1 answer:
lilavasa [31]3 years ago
4 0

I believe you're talking about displacement. It's a directional vector that depicts the movement of a point between two instances.

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A yellow banana reflects only yellow light,

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The data points you have taken on your lab graphs roughly form a straight line. How do you interpret the slope of this line?
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In metals, some electrons from the outer shells of atoms are shared with other atoms, with the result that electrons can freely
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<h2>Answer:Option F</h2>

Explanation:

Metals have few number of electrons in their valence shell.

The force with which the nucleus of the metal atom is pulling the electron towards itself is lower on the valence shell because the distance between the nucleus an valence shell is large.

So,there are a lot of free electrons in metals.

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4 years ago
DEVELOP SCIENCE CONCEPTS What kind of habitat do animals in<br> your community live in?
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3 years ago
1. A heat engine operates between two reservoirs at T2 = 600 K and T1 = 350 K. It takes in 1.00 x 103 J of energy from the highe
Alex73 [517]

Answer:

\Delta S_u=2.1429\ J.K^{-1}

W_c=416.67\ J

Explanation:

Given:

temperature of source reservoir, T_H=600\ K

temperature of sink reservoir, T_L=350\ K

energy absorbed from the source, Q_{in}=1000\ J

work done, W=250\ J

a.

<u>Now change in entropy of the surrounding:</u>

\Delta S_u=\frac{dQ_L}{T_L}

<em>Since heat engine is a device that absorbs heat from a high temperature reservoir and does some work giving out heat in the universe as the byproduct.</em>

\Delta S_u=\frac{Q_H-W}{T_L}

\Delta S_u=\frac{1000-250}{350}

\Delta S_u=2.1429\ J.K^{-1}

b.

<u>We know Carnot efficiency is given as:</u>

\eta_c=1-\frac{T_L}{T_H}

\eta_c=1-\frac{350}{600}

\eta_c=0.4167

<u>Now the Carnot work done:</u>

W_c=Q_H\times \eta_c

W_c=1000\times 0.4167

W_c=416.67\ J .......................(1)

c.

From eq. (1) we have the Carnot work, so the difference:

\Delta W=W_c-W

\Delta W=416.67-250

\Delta W=166.67\ J

Now, we find:

T_L.\Delta S_u=350\times 2.1429

5 0
3 years ago
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