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3 years ago

11

Michael's car ran over a nail, which made a hole in one of the tires. At what point will air stop pouring out of the hole in the

tire?

1 answer:

Ludmilka [50]3 years ago

8 0

The the pressure inside the tire has reached equilibrium with the outside pressure (14.7 PSI at sea level.)

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A charge Q is transferred from an initially uncharged plastic ball to an identical ball 17 cm away. The force of attraction is t

Alecsey [184]

Answer:

2.92 x 10¹² electrons

Explanation:

given,

distance between two plastic ball, r = 17 cm

r = 0.17 m

Force of attraction = F = 68 mN

F = 0.068 N

number of electron transferred from one ball to another.

using Coulomb Force equation

$F = \dfrac{kq^2}{r^2}$

$0.068 = \dfrac{9\times 10^9\times q^2}{0.17^2}$

q² = 2.1835 x 10⁻¹³

q = 4.67 x 10⁻⁷ C

now, number of electron

$N = \dfrac{q}{e}$

e is the charge of electron which is equal to 1.6 x 10⁻¹⁹ C

$N = \dfrac{4.67\times 10^{-7}}{1.6\times 10^{-19}}$

N = 2.92 x 10¹² electrons

electrons were transferred from one ball to the other is 2.92 x 10¹²

5 0

3 years ago

We can study how galaxies evolve because ________. We can study how galaxies evolve because ________. we are really smart astron

professor190 [17]

Answer:the farther away we look, the further back in time we see.

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4 years ago

Is density the degree of compactness of a substance?

san4es73 [151]

Yes it is, in other simplified terms density compares the amount of matter an object has to its volume.

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3 years ago

22. A 2.0 kg ball, traveling at 1.0 m/s, rolls off of a cliff of height 3.0 m. If the

RoseWind [281]

GOOD MORNING HAVE A NICE DAY

3 0

3 years ago

Help please, I don't get it

Sergio [31]

Answers:

a) $\hat F=(0.83,-0.55) N$

b) $\hat D=(-0.44,-0.89) m$

c) $\hat V=(-0.47,0.88) m/s$

Explanation:

A unit vector is a vector whose magnitude (length) is equal to 1. This kind of vector is identified as $\hat v$ and the way to calculate is as follows:

$\hat v=\frac{\vec v}{|v|}$

Where:

$\vec v=(x,y)$ is the vector

$|v|=\sqrt{x^{2}+y^{2}}$ is the magnitude of the vector

Having this information clarified, let's begin with the answers:

a) Force Vector

$\vec F=(9.0 \hat i - 6.0 \hat j) N$

Magnitude of $\vec F$ :

$|F|=\sqrt{(9.0 \hat i)^{2}+(-6.0 \hat j)^{2 }}N=10.81 N$

<u />

<u>Unit vector:</u>

$\hat F=\frac{\vec F}{|F|}$

$\hat F=\frac{(9.0 \hat i - 6.0 \hat j) N}{10.81 N}$

$\hat F=\frac{9.0}{10.81} N-\frac{6.0}{10.81}N$

$\hat F=(0.83,-0.55) N$

b) Displacement Vector

$\vec D=(-4.0 \hat i - 8.0 \hat j) m$

Magnitude of $\vec D$ :

$|D|=\sqrt{(-4.0 \hat i)^{2}+(-8.0 \hat j)^{2 }}m=8.94 m$

<u />

<u>Unit vector:</u>

$\hat D=\frac{\vec D}{|D|}$

$\hat D=\frac{(-4.0 \hat i - 8.0 \hat j) m}{8.94 m}$

$\hat D=\frac{-4.0}{8.94} Nm+\frac{-8.0}{8.94}m$

$\hat D=(-0.44,-0.89) m$

c) Velocity Vector

$\vec V=(-3.50 \hat i + 6.50 \hat j) m/s$

Magnitude of $\vec V$ :

$|V|=\sqrt{(-3.50 \hat i)^{2}+(6.50 \hat j)^{2}}m/s=7.38 m/s$

<u />

<u>Unit vector:</u>

$\hat V=\frac{\vec V}{|V|}$

$\hat V=\frac{(-3.50 \hat i +6.50 \hat j) m/s}{7.38 m/s}$

$\hat V=\frac{-3.50}{7.38} m/s+\frac{6.50}{7.38}m/s$

$\hat V=(-0.47,0.88) m/s$

8 0

4 years ago