Answer:
Total work done in expansion will be
Explanation:
We have given pressure P = 2.10 atm
We know that 1 atm
So 2.10 atm
Volume is increases from 3370 liter to 5.40 liter
So initial volume
And final volume
So change in volume
For isobaric process work done is equal to
So total work done in expansion will be
Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:
A skateboarder flies horizontally off a cement planter. After a time of 3 seconds (Δt), he lands with a final velocity (v) of −4.5 m/s. Assuming the acceleration is -9.8 m/s² (a), we can calculate the initial velocity of the skateboarder (v₀) using the kinematic equation A.
Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:
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Answer:
1) Current decreases; 2) Inverse proportionally; 3) 1[A]
Explanation:
1)
As we can see as the resistance increases the current decreases, if we take two points as an example, when the resistance is equal to 50 [ohms] the current is equal to 1[amp] and when the resistance is equal to 200 [ohms] the current tends to have a value below 0.5 [amp]. Thus demonstrating the decrease in current.
2)
Inverse proportionally, by definition we know that the law of ohm determines the voltage according to resistance and amperage. This is the voltage will be equal to the product of the voltage by the resistance.
where:
And whenever we have in a fractional number the denominator the variable we are interested in, we can say that this is inversely proportional to the value we are interested in determining. In this case, we can see from the two previous expressions that both the current and the resistance appear in the denominator, therefore they are inversely proportional to each other.
3)
If we place ourselves on the graph on the resistance axis, we see that at 50 [ohm] will correspond a current value equal to 1 [A].
For A 100-cm long dipole is excited by a sinusoidally varying current with an amplitude i0=2 , the time average power radiated is mathematically given as
P=0.1577w
<h3>What is the time average power radiated by the dipole if the oscillating frequency is 150 mhz?</h3>Generally, the equation for the is mathematically given as
Therefore
lambda=300m
In conclusion, for the power
P=0.1577w
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