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Anon25 [30]
3 years ago
15

488 J of work is done to a box which is moved across the floor for a distance of 8.9 m. What net force is required to act on the

box to do this amount of work?
Physics
1 answer:
kvv77 [185]3 years ago
8 0
According to the formula
a = f \times d
Where a is work, f is force and d is the distance that box was moved over. And from that formula, you can get that f = a/d and that is 54.83N of force
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22%

Explanation:

55 - 45 = 10

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A 6 kg box with initial speed 5 m/s slides across the floor and comes to a stop after 1.9 s. What is the coefficient of kinetic
Ilia_Sergeevich [38]

Answer:

\mu_k=0.27

Explanation:

According to the free body diagram, in this case, we have:

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Recall that the force of friction is given by:

F_k=\mu_k N

Replacing and solving for the coefficient of kinetic friction:

-\mu_kN=ma\\-\mu_k(mg)=ma\\\mu_k=-\frac{a}{g}

We have an uniformly accelerated motion. Thus, the acceleration is defined as:

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Finally, we calculate \mu_k:

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Answer:

D.

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