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Anon25 [30]
4 years ago
15

488 J of work is done to a box which is moved across the floor for a distance of 8.9 m. What net force is required to act on the

box to do this amount of work?
Physics
1 answer:
kvv77 [185]4 years ago
8 0
According to the formula
a = f \times d
Where a is work, f is force and d is the distance that box was moved over. And from that formula, you can get that f = a/d and that is 54.83N of force
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A car jumps off a ramp with a Kinetic energy of 5,000 joules. This same car has a gravitational potential energy of 4,685 joules
Sedaia [141]

Answer:

14,653 J.

Explanation:

We know that,

Total mechanical energy is equal to the sum of all the potential and kinetic energies.

Given,

Kinetic energy when a car jumps off a ramp= 5000 J

Potential energy = 4685 J

Potential energy when the car lands= 4968 J

TME = 5000 + 4685 + 4968

        = 14,653 J

Hence, the car's total mechanical engery is equal to 14,653 J.

3 0
3 years ago
A material allows charges to move freely through it. Which statement is the
Maslowich
The answer is D- it has a high resistance and is a conductor


hope this helps !
4 0
3 years ago
Read 2 more answers
Two workers are sliding 350 kgkg crate across the floor. One worker pushes forward on the crate with a force of 390 NN while the
svetoff [14.1K]

Answer:

\mu_k=0.18

Explanation:

First, we write the equations of motion for each axis. Since the crate is sliding with constant speed, its acceleration is zero. Then, we have:

x: T+F-f_k=0\\\\y:N-mg=0

Where T is the tension in the rope, F is the force exerted by the first worker, f_k is the frictional force, N is the normal force and mg is the weight of the crate.

Since f_k=\mu_k N and N=mg, we can rewrite the first equation as:

T+F-\mu_k mg=0

Now, we solve for \mu_k and calculate it:

\mu_k=\frac{T+F}{mg}\\ \\\mu_k =\frac{220N+390N}{(350kg)(9.8m/s^{2})} =0.18

This means that the crate's coefficient of kinetic friction on the floor is 0.18.

6 0
4 years ago
Question 36 pls<br> Physics
Lera25 [3.4K]

R=\frac{U}{I}=\frac{0.5V}{180\cdot10^{-6}A}\approx2.78k\Omega

7 0
3 years ago
Three different people weight a standard mass of 2.00 g on the same balance. Each person obtains a reading of 2.32 g for the mas
Lubov Fominskaja [6]

Answer: precise

Explanation:

Three different people weight a standard mass of 2.00 g on the same balance. Each person obtains a reading of 2.32 g for the mass of the standard. These results imply that the balance that was used is precise.

Precision can be defined as the closeness of measured values to each other, for a measuring equipment it is the closeness of the values of readings obtained at different times to each other. It does not necessarily means the measurements are accurate(closeness to the actual value). Therefore, in the case above where three different people measured the same mass on the same balance, and each of them obtained the same value which is different from the standard value. We can say the balance used is precise because the three readings are the same.

5 0
3 years ago
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