All categories

3 years ago

BA, BD and BF are angle bisector of ADF find N

Mathematics

1 answer:

Lunna [17]3 years ago

8 0

Answer:

n = 9

Step-by-step explanation:

BF is angle bisector of <AFE

<BFE = <AFB

3n - 3 = 24

3n = 27

n = 9

You might be interested in

What is the slope of the line that passes through the pair of points (-1, 4), (3,12)

Nadya [2.5K]

Answer:

$\displaystyle m = 2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Slope Formula: $\displaystyle m = \frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Identify

Point (-1, 4)

Point (3, 12)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]: $\displaystyle m = \frac{12-4}{3--1}$
[Fraction] Subtract: $\displaystyle m = \frac{8}{4}$
[Fraction] Divide: $\displaystyle m = 2$

3 0

3 years ago

Can you please tell me the first 20 digits of pi. I need o memorize them for a test

Andrew [12]

3.14159265358979323846

5 0

4 years ago

Bob deposits $3000 into an account that pays simple interest at a rate of 5% per year. How much interest will he be paid in the

Setler [38]

Answer:

He will have paid 750 interest in the first five years.

Step-by-step explanation:

SI = P×R×T/100

3000 x 5 x 5 divided by 100

75000 / 100 = 750

4 0

3 years ago

In how many ways can 6 competitors finish a race assuming there are no ties?In how many ways can we sit n people on r < n cha

VLD [36.1K]

Answer: a) 720, b) $^nC_r=\dfrac{n!}{(n-r)!r!}$ c) 336, d) 30240 e) 120.

Step-by-step explanation:

Since we have given that

a) Number of competitors = 6

We need to find the number of ways that 6 competitors can finish a race and there are no ties.

So, Number of ways would be

$6!=720$

b) number of people = n

Number of chairs = r (r<n)

so, the number of ways we can sit n people on r<n chairs is given by

$^nC_r=\dfrac{n!}{(n-r)!r!}$

c) If there are three awards :

Gold, silver, bronze.

We need to find the number of ways that these medals can be awarded.

Number of ways is given by

$^8P_3\\\\=336$

d) Number of 5-digit zip codes are possible is given by

$^{10}P_5=30240$

e) Number of poeple = 10

Number of people required in committee = 3

Number of different 3 person committee that are selected from 10 people is given by

$^{10}C_3=120$

Hence, a) 720, b) $^nC_r=\dfrac{n!}{(n-r)!r!}$ c) 336, d) 30240 e) 120.

6 0

3 years ago

Please PLEASE please!!! Any math experts can solve these I will give thanks and mark thank you!!!!

Alla [95]

Answer:

numerator: 3

denominator: 2

numerator: 2

denominator: 2

10.

numerator: 2

denominator: 4

6 0

3 years ago