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andre [41]
4 years ago
6

The width of a rectangle is equal to "m" cm, but its length is five times greater than the width. Find the area of the rectangle

.
m is the variable..not meters

PLEASE HELP ASAP!
Mathematics
2 answers:
Anvisha [2.4K]4 years ago
7 0

 

<h3>To eliminate confusion we use "a" instead of "m"</h3><h3>W = a cm</h3><h3>L = 5a cm</h3><h3>Area = W × L = a × 5a = 5a² cm²</h3>

nevsk [136]4 years ago
6 0

Answer: 5m^2 square centimeters.

Step-by-step explanation:

Given : The width of a rectangle is equal to "m" cm, but its length is five times greater than the width.

i.e. Expression for Width = m  and Length = 5 x m = 5m

We know that the area of a rectangle is given by :-

\text{Area=length x width}

Put Width = m  and Length = 5m , we get

Area of the rectangle = (5m) \times(m)= 5m^2 square centimeters.

Hence, the area of the rectangle = 5m^2 square centimeters.

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1080 degrees

Step-by-step explanation:

A regular octagon has 135 degrees per interior angle. To find the sum, add 135 for each angle. There are 8 interior angles.

8*135 = 1,080

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Which expression is equivalent to (8^-2)^-8?<br> a. 1/8^-10<br> b. 8^16<br> c. 1/8^16<br> d. 8^-10
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When you exponentiate an exponent you multiply the numbers,

So when we have (8^-2)^-8 it will be equal to
8^ (-2*-8) = 8^16

So B is our equivalent answer
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What is the equation of the line through the origin and (2, 5)?
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y=\frac{5}{2}x

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\frac{rise}{run}

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How much money is one third of $2.34
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Divide it by 3.
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3 years ago
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Answer the following
Amanda [17]

The set A satisfying the given inequality is A = (-\infty, -10].

<h3>What are some properties of an inequality relation? </h3>

Following are some facts which are true for an inequality relation:

  • Equal numbers can be added or subtracted from both sides of an inequality without affecting the inequality sign.
  • The Inequality sign is unchanged if both sides are multiplied or divided by a positive number, but when multiplied or divided by a negative number the inequality sign is reversed.

\frac{5x-2}{8} - \frac{3x-5}{10} &\ge& x+y\\\\\Rightarrow\;\; \frac{13}{40}x + \frac{1}{4}&\ge& x+y\\\\\Rightarrow\;\;\;\;\;\; -\frac{27}{40}x &\ge & y - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\;\; -x &\ge & \frac{40}{27}\left( y-\frac{1}{4} \right).\hspace{1cm}(1)

Since y ∈ B, -2 ≤ y ≤ 7. So,

\;\;\;\;\;\;\;\,-2 - \frac{1}{4}\; \le\; y - \frac{1}{4} \;\le\; 7 - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\; -\frac{9}{4}\; \le\;  y - \frac{1}{4} \;\le\; \frac{27}{4}\\\\\Rightarrow\;\;\; -\frac{9}{4}\cdot \frac{40}{27} \;\le\; \frac{40}{27} \left( y-\frac{1}{4} \right) \;\le \;\frac{27}{4}\cdot \frac{40}{27}\\\\\Rightarrow\;\;\;\;\;\;\;\; -\frac{10}{3} \;\le\; \frac{40}{27}\left( y - \frac{1}{4} \right)\; \le\; 10.

The set {-x | inequality (1) holds ∀ y ∈ B} is [10, \infty) i.e.

10 ≤ -x ≤ \infty.

Multiplying -1 throughout gives

-10 ≥ x ≥ -\infty.

x, thus, lies in the range A = (-\mathbf{\infty}, -10}.

Learn more about the inequality here.

brainly.com/question/17801003

Disclaimer: The question was incomplete. Please find the full content below.

<h3>Question </h3>

Find the set A such that for x ∈ A

\frac{5x - 2}{8} - \frac{3x - 5}{10} \ge x + y

∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.

#SPJ4

4 0
2 years ago
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