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zalisa [80]
3 years ago
10

Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $2,465 was collected on the sale of 1,077 ticket

s. How many of each type of ticket were sold?
Mathematics
2 answers:
frez [133]3 years ago
4 0
Assign x to adult tickets and y to student tickets, then set up the system
5x+y=2465 and
x+y=1077
You can subtract the second equation from the first to get
4x=1388
=> x=347
Then to find y do 1077-347 to find
y=730

Final answer:
347 adult tickets and 730 student tickets were sold.
Hope I helped :)
IrinaVladis [17]3 years ago
4 0
Let, the number of student tickets = x
Number of Adult's ticket = y

Equations = x + 5y = 2465
x + y = 1077

Subtract the equations, 
4y = 1388
y = 1388/4
y = 347

Substitute it in 2nd equation, 
x + 347 = 1077
x = 1077 - 347 = 730

In short, Student tickets = 730; Adult tickets = 347

Hope this helps!

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Can anyone figure this out for me please? It would be greatly appreciated.
Ira Lisetskai [31]
Check the picture below.

now, to get how much is the area of the tiled section, we simply get the area of the whole pool, 53x26, which includes the tiles, and then subtract the area without the tile, the rectangle in the middle, and what's leftover, is the area of the tiled area.

\bf 53-4\frac{1}{2}-4\frac{1}{2}\implies 53-9\implies \boxed{42}
\\\\\\
26-4\frac{1}{2}-4\frac{1}{2}\implies 26-9\implies \boxed{17}
\\\\\\
\textit{so the area of the rectangle in the middle is}\implies 42\cdot 17\implies 714
\\\\\\
\textit{and the area of the whole pool is}\implies 53\cdot 26\implies 1378

\bf \stackrel{\textit{area of the whole pool}}{1378}~~-~~\stackrel{\textit{area of the middle rectangle}}{714}\implies \stackrel{\textit{area of the tiles}}{664}\\\\
-------------------------------\\\\
\textit{we know that is }\$5\frac{1}{2}\textit{ for a foot of tile, then}\stackrel{\textit{price of the tiles}}{664\cdot 5\frac{1}{2}}\implies 3652

8 0
3 years ago
Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx
Soloha48 [4]

Answer:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

Step-by-step explanation:

For this case we need to find the following integral:

\int x(8-x)^{3/2}dx

And for this case we can use the substitution u = 8-x from here we see that du = -dx, and if we solve for x we got x = 8-u, so then we can rewrite the integral like this:

\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)

And if we distribute the exponents we have this:

\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du

Now we can do the integrals one by one:

\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C

And reordering the terms we have"

\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C

And rewriting in terms of x we got:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

And that would be our final answer.

8 0
3 years ago
Write an expression with two terms. One term should have a coefficient with a variable and the other term should be a constant.
soldier1979 [14.2K]

Answer:

See Explanation

Step-by-step explanation:

Let us briefly explain the terms

  • Variable: This is the letter in the expression
  • Coefficient: This is the number beside the letter above
  • Constant: This is a number without any variable attached.

Let us take our expression with two terms to be: 3x+5

Coefficient =3

Variable =x

Constant =5

The word phrase of the expression is:

5 added to the product of 3 and a number.

3 0
4 years ago
Write the equation of the parabola in vertex form.
stellarik [79]

well, looking at the picture of this vertically opening parabola, it has a vertex at 0,0 and it passes through 2,1 hmm ok

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8 0
3 years ago
6-(-12)= <br><br> 1/2 ÷ 3/4=<br><br> Plz answer quickly!
muminat

6-(-12)=18

1/2 ÷ 3/4=2/3

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3 years ago
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