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alukav5142 [94]
3 years ago
13

Rewrite the expression in the form x

Mathematics
1 answer:
Serga [27]3 years ago
5 0

Answer:

See below (I hope this helps!)

Step-by-step explanation:

When dividing exponential terms of the same base, we can simply subtract the exponents, therefore:

\frac{x^{6} }{x^{8} } = x^{(6-8)} = x^{-2}

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The smallest multiple of 50​
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Answer:

1

Step-by-step explanation:

One is the smallest multiple of 50. We can find this by finding all the multiples of 50. The multiples of 50 are: 1, 2, 5, 10, 25, and 50.

We can see that one is the smallest multiple because it is less than 2, 5, 10, 25 and 50. So, that means the answer to the question is 1.

Hope this helps.

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2 years ago
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2.38+4.89=3+ _ <br><br>changing expressions??
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3 years ago
The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

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slamgirl [31]

Answer:

(6/2)² = 3² = 9

6²/2² = 36/4 = 9

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2 years ago
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