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3 years ago

15

I don’t know how to solve this

2 answers:

White raven [17]3 years ago

8 0

Hi. First, you need to find the area of the inner shaded area and the outer area.

Find the inner shaded area: 4cm x 5cm = 20^2
Find the outer area: 7cm x 8cm = 56^cm

Okay now we subtract

56^2 - 20^2 = 36^2cm

Hope this helps.

Take care,
Diana

snow_lady [41]3 years ago

5 0

First you have to find the area of the WHOLE BOX. So you multiply,
8×7=56
Then find the area of the small box,
5×4=20
It says take away the area of the small box from the whole box and you should do just that: 56-20=36
The area of the shaded region is 36cm²

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2 years ago

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snow_lady [41]

Answer:

J

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If the side of the shape is increased by 3/2 then the total distance around the shape will be 3/2 bigger.

Example: If the pentagon has side length 2 then it becomes 2*3/2 = 6/2 = 3.

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2 years ago

Please help and thank you

tatiyna

Answer:

$b_{1}=\frac{2A}{h}-b_{2}$

Step-by-step explanation:

Given: $A=\frac{1}{2}(b_{1} +b_{2})h$

We need to completely isolate $b_{1}$ to solve.

$A=\frac{1}{2}(b_{1} +b_{2})h$

$A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h$

$A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}$

Finally, multiply both sides by -2 to completely isolate $b_{1}$ .

$b_{1}=\frac{2A}{h}-b_{2}$

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3 years ago

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