Answer:
Multiply vector c by the scalar -1/2.
Step-by-step explanation:
Look at vector c.
It has an x component of 4 and a y component of 4.
You can write vector c as a sum of its components using unit vectors in the x direction (i) and in the y direction (j).
c = 4i + 4j
Now look at vector d, and write it also as a sum of its x and y components.
d = -2i - 2j
Now ask yourself, what operation do I do to 4 to end up with -2?
One answer is to multiply 4 by -1/2.
d = (-1/2)c = (-1/2)(4i) + (-1/2)(4j) = -2i - 2j
That worked. By multiplying vector c by the scalar -1/2, you end up with vector d.
In calculus, we use derivatives to find the instantaneous rate of change at any point on a graph. To find the average rate of change, we just find the slope of the secant line that intercepts two points on the graph.
We find slope with the following equation:

In this case, we are looking for the slope from x = -1 to x = 1. We have both x values, so next we need the y values.
F(-1) = (-1)^2 - (-1) - 1 = 1
F(1) = (1)^2 - (1) - 1 = -1
Now plug in the x and y values to find the slope:
The answer is -1.
Answer:
9* 3 ^ (x-2)
Step-by-step explanation:
g(x) = 3^x
We know a^ (b) * a^(c) = a^ (b+c)
9* 3 ^ (x+2) = 3^2 * 3 ^(x+2) = 3^(2+x+2) = 3^x+4 not equal to 3^x
3*(9^(x+2)) = 3*3^2(x+2) = 3^1 * 3^(2x+4) =3^(2x+4+1) = 3^(2x+5) not equal
9* 3 ^ (x-2) = 3^2 * 3 ^(x-2) = 3^(2+x-2) = 3^x equal to 3^x
3*(9^(x-2)) = 3*3^2(x-2) = 3^1 * 3^(2x-4) =3^(2x-4+1) = 3^(2x-3) not equal
Answer:
Step-by-step explanation:
is an arithmetic progression with ratio=4
a1=5
a2=a1+4=5+4=9
a3=a2+4=9+4=13
...............
a n+1 = a n+4