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3 years ago

Which pair of triangles is congruent by asa?

Mathematics

2 answers:

ladessa [460]3 years ago

6 0

I believe it would be D.

Zolol [24]3 years ago

3 0

D; look up “ASA” for clarification

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The value of the 7 in 507,264 is 10 times the value of the 7 in which number?

monitta

The value of seven is in the thousands place and is 10 time the number seven if it were at the hundreds place, which is where 2 is.

7000=10 x 700
7000=7000

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3 years ago

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The following tape diagram describes the relationship between the amount of red paint and the amount of blue paint in a "Plummy

Triss [41]

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Step-by-step explanation:

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3 years ago

Enter the next 3 terms from the geometric sequence below.

Harlamova29_29 [7]

Answer:

-24, 48, -96

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The number before multiplies by -2.

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Hope this helps. Have a nice day.

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vlada-n [284]

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3 years ago

It is known that the straight line l is tangent to the circle x^2+y^2=4 at a point on the x-axis, and intersects with the straig

Talja [164]

Step-by-step explanation:

The general equation of a circle is

$(x \ - \ h)^2 \ + \ (y \ - \ k)^2 \ = \ r^{2}$ ,

where h and k forms the coordinates of the centre of the circle.

When the circle has a centre at the origin, the equation reduces into

. $x^2 \ + \ y^2 \ = r^2$ .

Now, we are interested in solving for the x-intercepts (the x-coordinates when the circle intersects the x-axis), of the circle

$x^2 \ + \ y^2 \ = \ 4$ .

Thus,

$x^2 \ + \ (0)^2 \ = \ 4 \\ \\ \\ \-\hspace{1.3cm} x^{2} \ = \ 4 \\ \\ \\ \-\hspace{1.4cm} x \ = \ \pm \ 2$ .

Geometrically speaking, the tangent to the circle at the point defined by one of the x-intercepts of the circle is actually a vertical line, more specifically the lines $x \ = \ \pm \ 2$ .

First and foremost, for the vertical line $x \ = \ 2$ , it intersects the straight line $y \ = \ \displaystyle\frac{1}{2}x$ , giving the y-coordinate for point P,

$y \ = \ \displaystyle\frac{1}{2}(2) \\ \\ \\ y \ = \ 1$ .

Hence, the coordinates of point P are $(1, \ 1)$ .

However, since there are no boundaries given in the question and a circle is symmetrical about its centre, thus, point P also exists when the vertical line $x \ = \ -2$ and interdects the straight line $y \ = \ \displaystyle\frac{1}{2}x$ .

$y \ = \ \displaystyle\frac{1}{2}(-2) \\ \\ \\ y \ = \ -1$ .

Therefore, the coordinates of point P are also $(1, \ -1)$ .

8 0

2 years ago

Which pair of triangles is congruent by asa?​

Which pair of triangles is congruent by asa?