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ivolga24 [154]
4 years ago
8

Volunteers at Sam's school use some of the student council's savings for a special project. They buy 8 backpacks for $9 each and

fill each backpack with paper and pens that cost $3. By how much did the school council's savings change because of this project?
Mathematics
1 answer:
Novay_Z [31]4 years ago
3 0


8 x $9 = $72.00

8 x $3 = $24.00

$72.00 + $24.00 = $96.00

savings changed by $96.00

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Answer:

14/5

Step-by-step explanation:

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In the ellipse, if c=6cm, and b=8cm, what is the length of the major axis?
kondor19780726 [428]

Answer:

Option B). 10 cm

Step-by-step explanation:

Distance between center and the focus of an ellipse is given by the formula,

c² = a² - b²

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Option (B) is the answer.

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He will take the first one at 2:00 pm and the other at 4:00 pm
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Item 16<br> Solve the equation.<br><br> −4/9f=−3
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Read 2 more answers
The expressions below model different possibilities for the area of a pool. Identify which of the following expressions have at
Anna007 [38]
<h3>Answer: Choice B is correct</h3>

========================================================

Explanation:

Use a graphing tool like GeoGebra, Desmos, or your graphing calculator to plot each expression given as a separate y equation. Four parabolas should result.

The x intercept is the same as the root or zero of a function.

You should find that only choice B has a root thats larger than 4. That specific root being x = 7.

----------------------------

A non-graphing approach:

You can use the quadratic formula or the factoring method to find the roots.

For choice A, it factors to (x+5)(x+6) = 0. The roots are x = -5 and x = -6 which aren't greater than 4. So we cross choice A off the list. Choices C and D are similar stories.

On the other hand, choice B factors to (x-7)(x+2) = 0 and it has roots of x = 7  and x = -2. This is another way to see why choice B is the answer.

Here are the steps for the quadratic formula for choice B

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-5)\pm\sqrt{(-5)^2-4(1)(-14)}}{2(1)}\\\\x = \frac{5\pm\sqrt{81}}{2}\\\\x = \frac{5\pm9}{2}\\\\x = \frac{5+9}{2} \ \text{ or } \ x = \frac{5-9}{2}\\\\x = \frac{14}{2} \ \text{ or } \ x = \frac{-4}{2}\\\\x = 7 \ \text{ or } \ x = -2\\\\

The quadratic formula is handy in case factoring is either not possible, or guess-and-check is too lengthy of a process. As you can probably tell, we could use the quadratic formula's results to help construct the factored form.

8 0
3 years ago
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