The height of the track will be given by:
sin θ=opposite/ hypotenuse
θ=34°4'=34+4/60=34 1/15°
thus
sin 34 1/15=h/68.8
h=68.8sin 34 1/15
h=38.54 meters
Well I don't know !
Let's check out the choices:
A). 3a - 4b = 21, a=0, b=7
3(0) - 4(7) = 21
0 - 28 = 21 Nope. That's not true.
B). 3a - 4b = 21, a=-3, b=2
3(-3) - 4(-2) = 21
-9 + 8 = 21
-1 = 21 Nope. That's not right.
C). 3a - 4b = 21, a=-2, b=-3
3(-2) - 4(-3) = 21
-6 + 12 = 21
6 = 21 Nope. That's not it.
Only one choice left.
This one had better be it:
D). 3a - 4b = 21, a=7, b=0
3(7) - 4(0) = 21
21 - 0 = 21
21 = 21 Yay ! That's it !
Answer: Adenike scored 64 marks, while Musa scored 45 marks
Step-by-step explanation: We shall start by assigning letters to each unknown variable. Let Adenike’s mark be d while Musa’s mark shall be m.
First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as
3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;
d = 19 + m ———(1)
3d/2 = 6 + 2m ———(2)
Substitute for the value of d into equation (2), if d = 19 + m
(3{19 + m})/2 = 6 + 2m
By cross multiplication we now have
3(19 + m) = 2(6 + 2m)
57 + 3m = 12 + 4m
We collect like terms and we have
57 - 12 = 4m - 3m
45 = m
We now substitute for the value of m into equation (1)
d = 19 + m
d = 19 + 45
d = 64
So Adenike scored 64 marks while Musa scored 45 marks
The answer for the question is 1/8
