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2 years ago

4. The first two numbers in a sequence are 3, 9.

Mathematics

1 answer:

UkoKoshka [18]2 years ago

5 0

The next two terms in the arithmetic progression will be 15 and 21.

Based on the information given, the following can be deduced.

First term = 3

Second term = 9

Common difference = 9 - 3 = 6

The nth term of an arithmetic progression is given as: = a + (n-1)d

Therefore, 3rd term = a + 2d = 3 + 2(6) = 3 + 12 = 15

4th term = a + 3d = 3 + 3(6) = 3 + 18 = 21

The next 2 terms are 15 and 21.

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3 years ago

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Which expression is equivalent to am ÷ an? am − n am + n am ⋅ n am ÷ n

tiny-mole [99]

The way it is written, none of them.

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Look at the image. (calculus)

mash [69]

<h3>Answer: Choice H) 2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is $\sin^2 x + \cos^2x = 1$

If we were to isolate sine, then,

$\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\$

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, $\cos x = \sqrt{1-\sin^2x}\\\\$

Cosine is also positive in this quadrant.

-------------

So,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2$

Therefore,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2$

is an identity as long as 0 < x < pi/2

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2 years ago

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The area A of a triangle with base b and height h is given by A = = bh. Find the area when b = 18 m (meters) and h = 30 m.

Pie

Answer:

$Area = 270m^2$

Step-by-step explanation:

Given

$A = \frac{1}{2}bh$

$b = 18m$

$h = 30m$

Required

Solve for A

Simply substitute 18 for b and 30 for h

$A = \frac{1}{2}bh$

$A = \frac{1}{2} * 18 * 30$

$A = 270$

Hence:

The area is

$Area = 270m^2$

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A hallway measuring 90 feet x 7 feet requires 1/2 a fluid ounce of cleaning solution per square foot. How much cleaning solution

Vilka [71]

315 fluid ounces of solution

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