Answer:

Step-by-step explanation:
We want to to rewrite

Use difference of two squares to get:

This implies that:


This finally simplifies to:

Therefore the required product is

<span>25 - (60% × 25) =
</span><span>25 - 60% × 25 =
</span>(1 - 60%) × 25 =
<span>(100% - 60%) × 25 =
</span><span>40% × 25 =
</span><span>40 ÷ 100 × 25 =
</span><span>40 × 25 ÷ 100 =
</span><span>1,000 ÷ 100 =
</span><span>10;
The answer is 10</span>
The answer is C that is X=7 and X=-1
multiple x through the given equation to get rid of a fraction. It will be

After that bring 6X to the LHS of the equation
so that it will look like the general equation that is

Use the quadratic formula (or any other approach to find the values of x
You will arrive at

Answer:
sorry to answer late but..
Step-by-step explanation:
= 
the wings of the real plane are 12 meters or 1200 cm
we want to solve for the scale, sooo do the algebra...get scale by it self..
real *
= scale
1200 *
= 16
The scale model wings are 16 cm 2.54 cm is one inch so the wings are approx. 6.3 inches
Answer:
rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour
Step-by-step explanation:
We will make a table of the trip there and back using the formula distance = rate x time
d = r x t
there
back
The distance there and back is 264 miles, so we can split that in half and put each half under d:
d = r x t
there 132
back 132
It tells us that the trip there is with the wind and the trip back is against the wind:
d = r x t
there 132 = (r + w)
back 132 = (r - w)
Finally, the trip there took 3 hours and the trip back took 6:
d = r * t
there 132 = (r + w) * 3
back 132 = (r - w) * 6
There's the table. Using the distance formula we have 2 equations that result from that info:
132 = 3(r + w) and 132 = 6(r - w)
We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:
132 = 3r + 3w and
132 - 3w = 3r so
44 - w = r. Subbing that into the second equation:
132 = 6(44 - w) - 6w and
132 = 264 - 6w - 6w and
-132 = -12w so
w = 11
Subbing w in to solve for r:
132 = 3r + 3(11) and
132 = 3r + 33 so
99 = 3r and
r = 33