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-BARSIC- [3]
3 years ago
6

What is an equation of the line that passes through the points (2, 1) and (6,-5)

Mathematics
1 answer:
marusya05 [52]3 years ago
4 0

Answer:

y=-1x+3

Step-by-step explanation:

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D-FIle her income taxes

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2 years ago
Adding negative numbers<br> Add.<br> -7 +4=
Bezzdna [24]

Hello!

-7 + 4 = -3

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3 years ago
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What is the gcf of 12 35 15
zaharov [31]
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6 0
3 years ago
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4x-6y=14 slope and y intercept?
alexandr1967 [171]

Answer:

m = 0.667

Step-by-step explanation:

Calculate and show the solution for the x-intercept and y-intercept of 4x - 6y = 14.

Calculate the graph plot coordinates for 4x - 6y = 14

Solve 4x - 6y = 14 for x and also for y.

Calculate and show the solution for the slope of 4x - 6y = 14

Find x-intercept

The x-intercept is where the graph crosses the x-axis. To find the x-intercept, we set y1=0 and then solve for x.

4x - 6y = 14

4x - 6(0) = 14

x1 = 3.5    y1 = 0

Find y-intercept

The y-intercept is where the graph crosses the y-axis. To find the y-intercept, we set x2=0 and then solve for y.

4x - 6y = 14

4(0) - 6y = 14

y2 = -2.333    x2 = 0

Get Graph Plot Coordinates

Getting two graph points will allow you to make a straight line on a graph. The plot coordinate format is (x1,y1) and (x2,y2).

Thus, we use the x-intercept and y-intercept results above to get the graph plots for 4x - 6y = 14 as follows:

(x1,y1) and (x2,y2)

(3.5,0) and (0,-2.333)

Find slope

The slope of the line (m) is the steepness of the line. It is the change in the y coordinate divided by the corresponding change in the x coordinate. Simply plug in the coordinates from above and solve for m to get the slope for 4x - 6y = 14

m = (y2 - y1)/(x2 - x1)

m = (-2.333 - 0)/(0 - 3.5)

m = 0.667

hope this is correct! c:

3 0
3 years ago
Read 2 more answers
62/45 in simplest form<br> (Please help)
nordsb [41]

Answer:

2 and 11/45

Step-by-step explanation:

If the fraction is improper you have to turn it into a mixed number. You can simplify the mixed number so the answer is 2 and 11/45.

7 0
3 years ago
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