(3t² +t -12t - 4)(t+2)=0
(3t³ - 5t² -26t -8) =0
t = -2
Answer:
Please check the explanation.
Step-by-step explanation:
Given that
|v|=38
Ф = 120°
<u>Finding the horizontal component</u>
The horizontal component can be obtained using the formula
Vx = |v| cos Ф
= 38 cos 120°
= 38 (-0.5)
= -19
Thus, the horizontal component is:
Vx = -19
<u>Finding the vertical component</u>
The vertical component can be obtained using the formula
Vy = |v| sin Ф
= 38 sin 120°
= 38 (0.86)
= 32.68
Thus, the vertical component is:
Vy = -19
- A vector 'v' with magnitude |v| and direction Ф can be written as:
v = |v| cos Ф i + |v| sin Ф j
As
|v|=38
Ф = 120°
Thus, the vector is
v = 38 cos 120° i + 38 sin 120° j
or
v = -19 i + 32.68 j
Answer:
I'm pretty sure that it's C.
The answer is <span>252.5 ft
</span><span>y = –0.004x</span>²<span> + x + 2.5
Let's take y = 0 and we'll get the quadratic equation:
</span>–0.004x² + x + 2.5 = 0
The general formula for quadratic equation is:
ax² + bx + c = 0
a = -0.004
b = 1
c = 2.5


Since distance cannot be negative (x1), the correct answer is x2 = 252.5 ft