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2 years ago

Modeling radioactive material decay by exponential function

Mathematics

1 answer:

ch4aika [34]2 years ago

7 0

ion really care bout school but i still go

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Can somebody please help (no websites)

const2013 [10]

Answer:

x y

0 .75

3 3.75

9 9.75

Step-by-step explanation:

You add .75 to whatever number x equals, to get y.

Hope that this helps!

4 0

2 years ago

PLEASE HELP! I ACCIDENTALLY STARTED THIS QUIZ TOO EARLY!

telo118 [61]

Answer:

inside

√((5-(-5))^2+((-24)-(-8))^2)=√(10^2+16^2)=√356＜25

4 0

2 years ago

How do you write 1.005 as a mixed fraction

bezimeni [28]

1 1/<span>200 should be the answer</span>

8 0

2 years ago

Read 2 more answers

Find the value of a.B.find the value of the marked angles

Bond [772]

Answer:

a. 18 b. 119°, 118°

Step-by-step explanation:

a. Given angles are vertical, so they are equal.

6a+11 = 2a+83

6a-2a = 83-11

4a = 72

a = 72/4

a = 18

b. Substituting the value of a in the given angles,

6a+11 = 6*18+11 = 108+11 = 119°

2a+83 = 2*18+83 = 36+83 = 118°

8 0

3 years ago

According to a poll, 55 % of Americans do not know that GOP stands for Grand Old Party (Time, October 17, 2011). Assume that thi

Ivenika [448]

Answer:

$\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$\mu_{\hat p} = 0.55$

And the deviation:

$\sigma_{\hat p} =\sqrt{\frac{0.55*(1-0.55)}{953}}= 0.0161$

Step-by-step explanation:

For this case we assume that the true population proportion of Americans do not know that GOP stands for Grand Old Party is 0.55 and we select a random sample of n = 953 americans

For this case we assume that we satisfy the conditions to use the normal approximation for $\hat p$

1) np >10 , n(1-p)>10

2) Independence

3) Random sample

4) The sample size is less than 10% of the population size

We assume that all the conditions are satisfied and the distribution for $\hat p$ would be:

$\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$\mu_{\hat p} = 0.55$

And the deviation:

$\sigma_{\hat p} =\sqrt{\frac{0.55*(1-0.55)}{953}}= 0.0161$

3 0

3 years ago