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ioda
3 years ago
10

A group of students conducted several trials of an experiment to study Newton’s second law of motion. They concluded that tripli

ng the mass required tripling the net force applied. What quantity were the students holding constant?
net force

acceleration <-- MY ANSWER

number of trials

mass
Mathematics
1 answer:
padilas [110]3 years ago
7 0

Answer:

Acceleration

Step-by-step explanation:

The Newton's second law of motion can be expressed as;

F = ma

Where F is the force acting on an object, m is the mass of the object and a is the acceleration of the object.

For an object of mass 2kg and acceleration of 5 m/s^{2}, we have;

F_{1} = 2 × 5 = 10 N

If we triple the mass,

m = 2 × 3 = 6 kg

Therefore,

F_{2} = 6 × 5 = 30 N

Thus, at constant acceleration, F_{2} = 3 × F_{1}

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Please help I don’t know it
navik [9.2K]

Answer:

109

Step-by-step explanation:

3 0
3 years ago
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Find a current example of a linear optimization model used in your industry. Describe the industry's needs, including any unique
marishachu [46]

Answer:

Follows are the explanation to the given question:

Step-by-step explanation:

Its determination of inventory amounts for various products. Its demand is an excellent illustration of a dynamic optimization model used in my businesses. Throughout this case, its store has restrictions within this room are limited. There are only 100 bottles of beverages to be sold, for instance, so there is a market restriction that no one can sell upwards of 50 plastic cups, 30 power beverages, and 40 nutritional cokes. Throughout this situation, these goods, even the maximum quantity supplied is 30, 18, and 28. The profit for each unit is $1, $1.4, and $0.8, etc. With each form of soft drink to also be calculated, a linear extra value is thus necessary.

5 0
3 years ago
Two cards are drawn with replacement, one after the other, and the outcomes recorded. What is the probability that at least one
babymother [125]

Answer:

The probability is 0.231

Step-by-step explanation:

In this question, we are tasked with calculating the probability that out of two cards drawn with replacement from a pack of cards , at least one of the two is a face card.

In a standard pack of cards, there are 52 cards.

Now let’s calculate the number of face cards we have.

There are 12 face cards in a pack of cards. There are 4 of each of Jack, Queen or King

The probability of drawing a face card is 12/52 = 3/13

Now, we want to calculate the probability of at least one of the cards drawn are face cards.

Mathematically, what we are needing to calculate is

Probability of drawing a single face card or probability of the two being a face card

Now let’s calculate.

The probability of the first card drawn being a face card is 3/13. The probability of the second card not being a face card will be 1-3/13 = 10/13

The joint probability under this first set of condition will be 3/13 * 10/13 = 30/169

Now, for the second condition, here we are considering that both cards drawn are face cards. What we have is 3/13 * 3/13 = 9/169

Now in probabilities, whenever we are having the statement or, we add the probabilities together

Thus, the probability here would be 30/169 + 9/169 = 39/169 = 3/13

In decimal this will be 0.231

8 0
3 years ago
Find the x-intercept<br> y = -3x + 12
Romashka-Z-Leto [24]

Answer:

x-intercept= -4

I could be wrong though

Step-by-step explanation:

3 0
3 years ago
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The notation f:S→T denotes that f is a function, also called a map , defined on all of a set S and whose outputs lie in a set T
AnnyKZ [126]

Answer:

There are many. Two examples are

f(x) = x, \\f(x) = x^3

Step-by-step explanation:

There are many examples. The simplest is

1 -

f(x) = x

It is trivial that

\text{if \,\,\,\,}  f(x) = f(y) \,\,\,\,\,\text{then} \,\,\,\,\, x=y

2 -

f(x) = x^3

That function is injective as well.

\text{if \,\,\,\,}  x^3 = y^3 \,\,\,\,\,\text{then} \,\,\,\,\, x=y

An example of a function that is NOT injective is

f(x) = x^2

Notice that

f(-2) = (-2)^2 = 2^2 = 4

4 0
3 years ago
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