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ioda
3 years ago
10

A group of students conducted several trials of an experiment to study Newton’s second law of motion. They concluded that tripli

ng the mass required tripling the net force applied. What quantity were the students holding constant?
net force

acceleration <-- MY ANSWER

number of trials

mass
Mathematics
1 answer:
padilas [110]3 years ago
7 0

Answer:

Acceleration

Step-by-step explanation:

The Newton's second law of motion can be expressed as;

F = ma

Where F is the force acting on an object, m is the mass of the object and a is the acceleration of the object.

For an object of mass 2kg and acceleration of 5 m/s^{2}, we have;

F_{1} = 2 × 5 = 10 N

If we triple the mass,

m = 2 × 3 = 6 kg

Therefore,

F_{2} = 6 × 5 = 30 N

Thus, at constant acceleration, F_{2} = 3 × F_{1}

You might be interested in
According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe
Ann [662]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 22% of couples meet online, hence p = 0.22.
  • A sample of 150 couples is taken, hence n = 150.

Item a:

The mean and the standard error are given by:

\mu = p = 0.22

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 0.25</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{0.25 - 0.22}{0.0338}

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the <u>p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15</u>, hence:

X = 0.2:

Z = \frac{X - \mu}{s}

Z = \frac{0.2 - 0.22}{0.0338}

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.22}{0.0338}

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

4 0
2 years ago
Help is greatly appreciated:)
Murrr4er [49]
Well there are 6 units down and 11 units across so 6•11=66. there are 14 red units. 66-14=52. the area of yellow is 52.
4 0
3 years ago
Find the 20th term in arithmetic sequence -4, 1, 6, 11, 16,
givi [52]
91, I just kept adding 5 until I got to the 20th term

7 0
3 years ago
Another easy one
andreyandreev [35.5K]
The limit is equivalent to the value of the derivative of \cos x at x=\dfrac\pi2. (See definition of derivative)

(\cos x)'=-\sin x\implies (\cos x)'\bigg|_{x=\pi/2}=-\sin\dfrac\pi2=-1
4 0
3 years ago
Find the sum of -1.5 +3.5 + 2
GarryVolchara [31]

Answer:

4, see below :)

Step-by-step explanation:

We can rewrite the equation into:

3.5 + 2 - 1.5

First we add 3.5 and 2

3 and 2 are in the ones place so:

5, and then you added the .5

5.5

Then:

5.5 - 1.5

First we subtract the tenths place so:

.5 - .5 = 0

Then the ones:

5 - 1 = 4

6 0
3 years ago
Read 2 more answers
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