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Svetradugi [14.3K]
3 years ago
7

.686 rounded to the nearest tenth

Mathematics
2 answers:
maria [59]3 years ago
8 0
.690 because 6 rounds up to 10 so it would go up to the next tenth
rodikova [14]3 years ago
7 0
I agree with her if you search it up you will get the same answer.
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The bases of a circular cylinder are two ___ circles.
Blababa [14]
Well,

A cylinder is actually a special type of prism.  A prism is a 3-D figure made by taking a simple closed plane curve and translating it across space in a certain direction and for a given distance and then connecting the preimage and the image.  A cylinder is just a prism made with a circle.

We know from translations that the image is congruent to the preimage.  Thus, the bases of a (circular) cylinder are two congruent circles.
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3 years ago
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Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
ВС<br> Round your answer to the nearest hundredth.<br> B.<br> ?<br> 35°<br> A<br> 2.<br> с
Akimi4 [234]

Answer:

a diagram is necessary. please provide a diagram.

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Furkat [3]

Answer:

the answer is 2100

Step-by-step explanation:

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The answer is x=20. You isolate the square root. Eliminate the radical on the left handside. And then solve it!
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