Given the height of the tree and the angle of elevation from point B, the distance between the tree is from point B is approximately 70ft.
<h3>What is the distance between the tree and point B?</h3>
Given the data in the question;
- Height of tree opposite angle of elevation = 34ft
- Angle of elevation θ = 26°
- Distance between tree and point B| Adjacent = ?
Since the scenario form a right angle triangle, we use trig ratio.
tanθ = Opposite / Adjacent
tan( 26° ) = 34ft / x
We solve for x
x = 34ft / tan( 26° )
x = 34ft / 0.4877
x = 70ft
Given the height of the tree and the angle of elevation from point B, the distance between the tree is from point B is approximately 70ft.
Learn more about trigonometric ratio here: brainly.com/question/28038732
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Answer:
(a)2(89x+84)
(b)
Step-by-step explanation:
The dimensions of the larger rectangular field are:
- Length=5x + 12; Width
= 9x + 14.
The dimensions of the smaller rectangular soccer field are:
(a)Area of the part of the field that is outside the soccer field
=Area of the larger rectangular field - Area of the Soccer Field
=(5x+12)(9x+14)-5x(9x)
=(5x)(9x)+70x+108x+168-5x(9x)
=178x+168
=2(89x+84)
(b)Radius of the Semicircular Fountain =2x
From Part (a),
Area of the larger rectangular field - Area of the Soccer Field=178x+168
Area of the Semicircular Fountain =
Area of the Field that does not include the soccer field or the fountain.
=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain
Answer:
the answer is A) 12,6. .
Step-by-step explanation:
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Answer:
look above
Step-by-step explanation:
hope it hepls
