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Basile [38]
2 years ago
15

Mia is taking art and calculus courses on Mondays. She is late for the art class with probability 0.5 and late for the calculus

class with probability 0.4. Suppose the two events are independent. What is the probability that Mia is on time to exactly one of the classes (write it up to first decimal place)?
Mathematics
1 answer:
padilas [110]2 years ago
7 0

Answer:

0.5

Step-by-step explanation:

Let the probability of being late for Art class be a = 0.5 and the probability of being on time for Art class be b = 1 - a = 0.5

Let the probability of being late for Calculus class be c = 0.4 and the probability of being on time for Calculus class be d = 1 - a = 0.6

Probability of being on time in exactly one of the classes = Probability of being ((on time for Art and late for Calculus) or (on time for Calculus and late for art))

= (b × c) + (d × a) = (0.5 × 0.4) + (0.6 × 0.5) = 0.2 + 0.3 = 0.5

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In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

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Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

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Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

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