Answer:
The correct option is;
∠AQS ≅ ∠BQS when AS = BS
Step-by-step explanation:
Given that AQ is equal to BQ. When AS is drawn congruent to BS, we have;
QS is congruent to SQ by reflective property
Therefore;
The three sides of triangle QAS are congruent to the three sides of triangle QBS, from which we have;
∠AQS and ∠BQS are corresponding angles, therefore;
∠AQS ≅∠BQS because corresponding angles of congruent triangles are also congruent.
The length of OM is 4/3 the length of OJ, and the length of ON is 4/3 the length of OK. Thus, two pairs of sides from the triangles are proportional to each other.
Also, angle O from one of the triangles is equal to angle O of the other triangle because they are the same angle.
Thus, the two triangles are similar by SAS (side-angle-side) similarity theorem. This theorem is quite similar to the SAS congruence theorem.
To make a similarity statement, we just have to match corresponding parts when naming the triangle.
Similarity statement: ΔOJK~ΔOMN
Answer:
12.4 mg
3117.21 mg
1870.32 mg
Step-by-step explanation:
Answer:
A. -2
Step-by-step explanation:
-25p - 2 = 48
First, add 2 to both sides
That gives you
-25p = 50
Then, divide both sides by -25. Then that leaves the answer.. p = -2
Answer:
t = 9 s
Step-by-step explanation:
A stone is thrown downward with an intitial velocity of 29.5 m/sec will travel a distance of a meters, where
We need to find when the stone will hit the ground. It means when s(t) = 0. So,
So, the stone will take 9 seconds to hit the ground. Hence, this is the required solution.