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3 years ago

A rectangular swimming pool is 15 meters long, 11 1/2 meters wide, and 1 1/2 meters deep. What is its volume?

1 answer:

3 0

258 3/4 cubic meters

Explanation:
Use this formula for volume of rectangular prism: length x width x height

In this case it would be:
15 • 11 1/2 • 1 1/2 = 258 3/4

VOLUME= 258 3/4 cubic meters

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Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

Help me plsssss I am failing in this class pls give me step by step

Vinvika [58]

Y=-3x+2 bc the line is going down so it’s negative and the y intercept is 2

5 0

2 years ago

Read 2 more answers

If you have 3 sticks of length 2 cm, 3 cm and 5 cm. What kind of triangle these sticks would form? Justify your answer.

stepan [7]

Answer:

Scalene triangle (As the definition says)

3 0

2 years ago

Given you or a person holding a kite string 100 feet long write and draw what the height or altitude the kite is off the ground

Salsk061 [2.6K]

Answer: $75.47\ ft$

Step-by-step explanation:

Given

String of the kite is $l=100\ ft$

Angle of elevation $\theta=49^{\circ}$

suppose altitude of the kite is h

from the figure, we can write

$\Rightarrow \sin 49^{\circ}=\dfrac{h}{100}\\\\\Rightarrow h=100\sin 49^{\circ}\\\\\Rightarrow h=75.47\ ft$

Thus, the altitude of the kite is $75.47\ ft$

8 0

3 years ago

Solve the following question algebraically, show your work<br><br> 13 + w/7 <-(fraction) = -18

evablogger [386]

Solve for w: by simplifying both sides of the equation, then isolating the variable.

w=-217

Work: 1. Subtract 13 from both sides (w/7 = -18 - 13), 2.Simplify -18-13 to -31 (w/7=-31), 3.Multiply both sides by 7 (w = -31 * 7), 4. Simplify 31*7 to 217 (w=-217)

8 0

3 years ago