Solve equation for y.
5x - y = 3
-y = -5x + 3
y = (-5x + 3)/(-1)
y = 5x - 3
The slope for this equation is 5.
The slope of the equation we want is the negative reciprocal of 5.
Let m = slope of equation we want.
m = -1/5
We are given the point (10,4).
Plug both into the point-slope formula.
y - 4 = (-1/5)(x - 10)
y - 4 = (-1/5)x + 2
y = (-1/5)x + 2 + 4
The equation we want is
y = (-1/5)x + 6
Did you follow?
You must use the Order of Operations
Parentheses
Exponents
Multiply
Divide
Add
Subtract
Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
41. Degree 3 = x^3 (maximum power in the equation)
Zeros: -1, 1, 3
(x-1)(x+1)(x-3)=f(x) <--- expand as necessary
44. Zeros: -4, 0, 2
(x+4)x(x-2)= f(x) <--- expand as necessary
47. Multiplicity is how many times a particular number is 0 for a given function.
(x+1)(x-1)^3(x-2)^3 <-- not too sure about this one, google definition of multiplicity?
Hope I helped :)
