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<span>The Answer is 5200 Joules</span>
More massive attacking objects speed slows down and it transfer its some kinetic energy to less massive target objects whereas less massive target objects starts its motion
Answer:
A = B = C > D
Explanation:
Work done to stop the disc is given as
![W = \Delta K](https://tex.z-dn.net/?f=W%20%3D%20%5CDelta%20K)
![W = \frac{1}{2}I(\omega_f^2 - \omega_i^2)](https://tex.z-dn.net/?f=W%20%3D%20%5Cfrac%7B1%7D%7B2%7DI%28%5Comega_f%5E2%20-%20%5Comega_i%5E2%29)
so we have
(a) –2 rad/s, 5 rad/s;
(b) 2 rad/s, 5 rad/s;
(c) –2 rad/s, –5 rad/s; and
(d) 2 rad/s, –5 rad/s.
So we have
![W_a = W_b = W_c = \frac{1}{2}I(5^2 - 2^2)](https://tex.z-dn.net/?f=W_a%20%3D%20W_b%20%3D%20W_c%20%3D%20%5Cfrac%7B1%7D%7B2%7DI%285%5E2%20-%202%5E2%29)
![W_d = \frac{1}{2}I(2^2 - 5^2)](https://tex.z-dn.net/?f=W_d%20%3D%20%5Cfrac%7B1%7D%7B2%7DI%282%5E2%20-%205%5E2%29)
so we have
A = B = C > D
Answer:
Explanation:
As per the Kepler's law of planetary motions :
1- The orbits are of elliptical shape having two foci and Sun is located on one foci.
2- The line segment that joins a planet and the Sun sweeps out equal are at equal interval of time.
3- The orbital period square is directly proportional to the cube of semi major axis of its orbit.
Kepler's law are applied on each of the planets of our solar system as the distance of the Sun from the planet is calculated through this.
For example : from Kepler's first law we can see the eccentricity of the Earth's orbit is 0.0167.