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BlackZzzverrR [31]
3 years ago
10

If you used 650 W of power lifting a 300 N weight in 2 seconds how high did you lift?

Physics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

4.33m

Explanation:

Power = work done/ time

work done = power × time =650 × 2 = 1300J

work done = force × distance

distance = work done/force

distance = 1300/300 = 4.33m

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What is the nature of force between two charges if q1+q2=0
MAXImum [283]
Answer:
The force will be attractive.


Explanation:
Since we the sum of the charges is 0 they must have opposite charges and equal magnitudes.

And Opposite charges are attaractive towards each other.
3 0
4 years ago
A proton initially at rest is accelerated by a uniform electric field. The proton moves 4.76 cm in 1.10 x 10^-6 s. Find the volt
iVinArrow [24]

Answer:

The voltage drop through which the proton moves is 39.1 V.

Explanation:

Given that,

Distance = 4.76 cm

Time t=1.10\times10^{-6}\ s

We need to calculate the acceleration

Using equation of motion

s = ut+\dfrac{1}{2}at^2

Where, s = distance

a = acceleration

t = time

Put the value in the equation

4.76\times10^{-2}=\dfrac{1}{2}\times a \times(1.10\times10^{-6})^2

a=\dfrac{2\times 4.76\times10^{-2}}{(1.10\times10^{-6})^2}

a=7.87\times10^{10}\ m/s^2

We need to calculate the voltage drop

Using formula of electric field

F=qE

F = q\dfrac{V}{d}....(I)

Using newton's second law

F = ma....(II)

Put the value of F in equation (I) from equation (II)

ma=\dfrac{qV}{d}

V=\dfrac{mad}{q}

Where, q = charge

a = acceleration

d = distance

m= mass of proton

Put the value into the formula

V=\dfrac{1.67\times10^{-27}\times7.87\times10^{10}\times4.76\times10^{-2}}{1.6\times10^{-19}}

V=39.1\ V

Hence, The voltage drop through which the proton moves is 39.1 V.

8 0
3 years ago
What is the net force? <br><br> URGENT! thank you
alexandr402 [8]
Net force is the vector sum of forces acting on a particle or body. The net force is a single force that replaces the effect of the original forces on the particle's motion. It gives the particle the same acceleration as all those actual forces together as described by the Newton's second law of motion.
6 0
4 years ago
A substance is soluble in water. It is added into the water and dissolves. More solute continues being added until it reaches a
Sophie [7]

Answer:

option D

Explanation:

also to add.... there exists a solubility equilibrium between solid solute and the solution.

4 0
3 years ago
A 4.8-kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t=0 s, the blo
garri49 [273]

Answer:

E) 80 N/m

Explanation:

Given;

mass of the block, m = 4.8 kg

displacement of the block, x = -0.5 m

velocity of the block, v = -0.8 m/s

acceleration of the block, a = 8.3 m/s²

From Newton's second law of motion;

F = ma

Also, from Hook's law;

F = -Kx

where;

k is the force constant

Thus, ma = -kx

k = -ma/x

k = -(4.8 x 8.3) / (-0.5)

k = 79.7 N/m

k ≅ 80 N/m

Therefore, the force constant of the spring is closest to 80 N/m

4 0
3 years ago
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