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BlackZzzverrR [31]
3 years ago
10

If you used 650 W of power lifting a 300 N weight in 2 seconds how high did you lift?

Physics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

4.33m

Explanation:

Power = work done/ time

work done = power × time =650 × 2 = 1300J

work done = force × distance

distance = work done/force

distance = 1300/300 = 4.33m

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If a 8860 N horse has been lifted 4.5 meters by a crane, what work does it have?
Lana71 [14]
<span>Data:
W (work) = ? (Joule)
P (weight) = 8860 N
h (height) = 4.5 m

Formula:
</span>W = P*h
<span>
Solving:
</span>W = P*h
W = 8860*4.5
\boxed{\boxed{W = 39870\:Joule}}\end{array}}\qquad\quad\checkmark
<span><span>

</span></span>
4 0
3 years ago
Show with proof, the planet which an astronaut would have a greater weight if Planet A has twice the mass and twice the radius o
meriva

Answer:

First let's look at the gravitational formula by newton:

f = g \times  \frac{m1 \times m2}{ {r}^{2} }

Now the f and g should be capital but that's not possible with the equation system. But we can see that the force the astronaut is pulled at is dependent on the mass and the distance if we assume his mass stays the same (mass and weight aren't the same also g is a constant). If a planet has twice the radius the force will by four times as weak because of the ^2. This is not compensated by the twice as big mass. Therefore the astronaut will have a higher force and thus a higher weight on planet B

4 0
3 years ago
A 5.2 cm diameter circular loop of wire is in a 1.35 T magnetic field. The loop is removed from the field in 0.29 sec. Assume th
Katyanochek1 [597]

Answer:

9.88 milivolt

Explanation:

Given: diameter d = 5.2 cm

magnetic field B_1 = 1.35 T, final magnetic field B_2 =0 T

t = 0.29 sec.

we know emf =  - dΦ/dt

and flux Φ = BA

A= area

therefore emf ε = -A(B_2-B_1)/Δt

=-\pi(d/2)^2\frac{B_2-B_1}{\Delta t} \\=-\pi(0.052/2)^2\frac{0-1.35}{0.29} \\=98.8\times10^4\\=9.88 mV

3 0
3 years ago
At some point in an underground horizontal pipe, the speed of water is 2.5m/s and the gauge pressure is 2×104 Pa. What is the ga
lys-0071 [83]

The gauge pressure of the pipe is  2.234 ×10⁴  Pa, if the pipe is changed for another twice the area.

To find the gauge pressure the values given are,

speed of water = 2.5 m/s

Gauge pressure = 2×10⁴  Pa

<h3>What is pressure?</h3>

Definition:

      Pressure can be defined as the total applied force per unit of area. The pressure depends both on externally applied force as well the area on which it is applied.

To find the gauge pressure first we have use continuity equation,

A ₁V₁ = A₂V₂

By the given condition: As the area is increased to twice the original area

A ₁V₁ = 2A₁V₂

A₁ gets cancelled on both the sides,

V₂ =V₁/2

    =2.5 /2

V₂=1.25 m/s

Then, substituting the values in Bernoulli's equation,

Equation is given as,

P₁ + 1/2 ρV₁² = P₂ + 1/2 ρV₂²

Taking 1/2 ρ as common,

P₂ =  2×10⁴ + 1/2 ×1000×(2.5² -1.25²)

    = 2×10⁴ + 2343.75

    =22343.75 Pa

    =2.234 ×10⁴ Pa

Thus, if the pipe is changed for another twice the area then the gauge pressure is 2.234 ×10⁴ Pa.

Learn more about pressure,

brainly.com/question/14012416

#SPJ1

6 0
1 year ago
Plz answer #2 plz this is 8th grade science / physics
MrRissso [65]
All you need is your science book
5 0
3 years ago
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