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Stels [109]
2 years ago
7

With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s

Physics
1 answer:
Dima020 [189]2 years ago
4 0
  • initial velocity=u=20km/h=5.5m/s
  • Acceleration=a=8m/s^2
  • Time=t=10s

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2

\\ \sf\longmapsto s=55+4(5.5)^2

\\ \sf\longmapsto s=55+4(30.25)

\\ \sf\longmapsto s=55+121

\\ \sf\longmapsto s=176m

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3 years ago
You have a horizontal grindstone (a disk) that is 86 kg, has a 0.33 m radius, is turning at 92 rpm (in the positive direction),
Rudiy27

Answer:

a) α = 0.338 rad / s²  b)   θ = 21.9 rev

Explanation:

a) To solve this exercise we will use Newton's second law for rotational movement, that is, torque

    τ = I α

    fr r = I α

Now we write the translational Newton equation in the radial direction

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The moment of inertia of a saying is

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Let's replace in the torque equation

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b) let's use the relationship of rotational kinematics

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    0 = w₀² - 2 α θ

    θ = w₀² / 2 α

Let's reduce the angular velocity

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    θ = 9.634 2 / (2 0.338)

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Let's reduce radians to revolutions

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7 0
3 years ago
A force of 450 N accelerates a box across a frictionless surface at a rate of 15 m/s 2 . What is the mass of the box? 30 N 30 kg
Elza [17]
Hey there,

Your correct answer would be 30kg.

450 = m × 15 or also 450/15=m.

Hope this helps.

~Jurgen
3 0
3 years ago
Read 2 more answers
A block of mass m begins at rest at the top of a ramp at elevation h with whatever pe is associated with that height.
natka813 [3]
 <span>PE = mass * height * g = 87.60 J 

Frictional force = m * g * sin theta * uk = 4.7 kg * 9.81 m/sec^2 * sin 36.87 * 0.3 = 8.299 N 

Work done by friction = force * distance = 41.50 J 

Remaining energy to be converted to KE = 87.60 J - 41.50 J = 41.10 J</span>hope it helps
8 0
3 years ago
Read 2 more answers
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