2x2x2=8
4x4=16
16x8=128
Hope this helps
Answer:
(Choice A) A graph of an increasing linear function in quadrant 1 with a positive y-intercept.
Step-by-step explanation:
The weight of the sumo wrestler starts at a positive value of 79.5 kilograms, and we are given that the sumo wrestler gains a linear amount of weight per month at 5.5 kilograms per month.
If we were to graph this relationship, the sumo wrestler's weight would be represented on the y-axis, and the amount of time on the x-axis.
So the initial weight would occur at (0, 79.5) which is the positive y-intercept.
And since his weight is increasing at 5.5 kilograms per month, the slope of the linear function is positive.
Hence, the graph of the linear increasing function in quadrant 1 with a positive y-intercept.
Cheers.
You have to use your standard normal table (or calculator) for these. The area under the curve should be 1, a z-value corresponds to the probability and is area to the left of that z.
a. A simple reverse lookup of 0.9750. z=1.96
b. Total area up to z would be 0.5+0.4750, so reverse look up 0.9750 and find z=1.96
c. A simple reverse lookup. z=0.61
d. Area to the left of z would b 1-0.1314, so lookup 0.8686 and find z=1.12
e. A simple reverse lookup. z=0.44
f. Just invert the area: 1-0.33 = 0.67 and reverse lookup: z=0.44
3(4) + 12 + 12[4(6) - 10]
12 + 12 + 12(24 - 10)
12 + 12 + 288 - 120
192
