The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= 
...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (
= k
k=
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The answer would be B. If you want to FIND how many points a person has, you put the "p" on its own on the left of the equation, and since every field goal (f) you score is worth 3 points, just multiply "f" by 3 (3f).
For example, if someone scored 5 field goals in a game, to find how many points they totalled, just plug in the 5 for "f":
1. Get equation:
p = 3f
2. Plug in field goals for "f":
p = 3(5)
3. Solve:
p = 15
2 . You have to divide 16 by 8. you get 2 . Hoped that helped
No, Alex is wrong. The correct expanded form would be 100+60+5+.03+.008
