THE ANSWER IS:
Q=98
P=25
R=57
STEP BY STEP EXPLANATION AND DOUBLE CHECKING:
1. Because you’re trying to find the variable for INTERNAL angles, all the angles will add up to 180. So, you put all the angles = 180
5x+3+3x+x+6=180
2. Add up all like terms
5x+3+3x+x+6 —> 9x+9=180
3. Subtract 9 from both sides
9x+9=180 —> 9x=171
4. Divide
9x=171 —> x=19.
TO DOUBLE CHECK THE ANSWER:
Plug 19 into all the variables.
ANGLE Q —> 5x+3 —> 5*19+3 —> 98
ANGLE P —> x+6 —> 19+6 —>25
ANGLE R —>3x —> 3*19 —> 57
Hope i helped :)
Answer:
A
Step-by-step explanation:
volume of cylinder= πr²h
r= 12cm
h = 19cm
putting the values in the formula
so these two lines intersect at x = 3 hmmmm what's the y-coordinate of the second line at that point?
![\bf 2x-3y=6\implies \stackrel{\textit{using x = 3}}{2(3)-3y=6}\implies 6-3y=6\implies -3y=0\implies y=0](https://tex.z-dn.net/?f=%5Cbf%202x-3y%3D6%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20x%20%3D%203%7D%7D%7B2%283%29-3y%3D6%7D%5Cimplies%206-3y%3D6%5Cimplies%20-3y%3D0%5Cimplies%20y%3D0)
so the y-coordinate of that second line is 0, so the point there is (3, 0) then.
so the first line is, a line that has a slope of 2 and passes through (3, 0).
![\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{0})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=2(x-3)\implies y=2x-6](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B3%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29~%5Chspace%7B10em%7D%20slope%20%3D%20m%5Cimplies%202%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-0%3D2%28x-3%29%5Cimplies%20y%3D2x-6)