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diamong [38]
4 years ago
15

PLEASE I NEED THIS ANSWERED ASAP

Chemistry
1 answer:
kherson [118]4 years ago
7 0
The answer would be: 
A. Cancel out CO because it appears as a reactant in one intermediate reaction and a product in the other intermediate reaction.

In this question, there are two half-reaction equations. To merge them up, you need to add the reactant with the reactant, then the product with the product. If there is a molecule on both side, you can cancel them. The full reaction would be:

C+ 1/2 O2 + CO + 1/2O2 ==>CO+ CO2       -----> remove CO from both side
C+ O2 ==>CO2
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Using the bond energy data from your text (or the internet), determine (show calculations for) the approximate enthalpy change ,
aleksley [76]

Answer:

∆H=  <u>438 KJ/mol</u>

Explanation:

First, we have to find the <u>energy bond values</u> for each compound:

-) Cl-Cl = 243 KJ/mol

-) F-F = 159 KJ/mol

-) F-Cl = 193 KJ/mol

If we check the reaction we can calculate the <u>number of bonds</u>:

Cl_2_(_g_)~+~3F_2_(_g_)~->~2ClF_3_(_g_)

In total we will have:

-) Cl-Cl = 1

-) F-F = 3

-) F-Cl = 6

With this in mind. we can calculate the <u>total energy for each bond</u>:

-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol

-) F-F = (3*159 KJ/mol) = 477 KJ/mol

-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol

Now, we can calculate the total energy of the <u>products</u> and the <u>reagents</u>:

Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol

Products = 1158 KJ/mol

Finally, to calculate the total enthalpy change we have to do a <u>subtraction</u> between products and reagents:

∆H= 1158 KJ/mol-720 KJ/mol = <u>438 KJ/mol</u>

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I hope it helps!

7 0
3 years ago
Which of the following statements describe what a normative system is?​
natta225 [31]

Explanation:

though the statements were not given let just give you a brief review of normative system.

A normative statement explains what should be base of the subject according to the belief through valued judgement that describes the fairness of the subject on public policy. Therefore, the unemployment rate should be lowered is a valued judgement based on the belief that it will bring economic welfare.

Normative systems, i.e., sets of norms, have two main. tions: a) to evaluate human actions, and b) to guide peop. The guidance and the evaluation based on a normativ. be good or bad.In social psychology three different normative behaviours have been identified: obedience, conformity and compliance.In the context of a normative system like law (or religion or morality), every statement of what one ought to do (or ought not to do) requires justification from a more general or basic statement. Such statements lead upward through the normative hierarchy until one reaches a foundational normative premise.

please rate brainliest if helps and follow

4 0
2 years ago
Compared to the mass and the penetrating power of an alpha particle, a beta particle has(1) less mass and greater penetrating po
seropon [69]

Answer is (1) - less mass and greater penetrating power.


Alpha particle is a ₂⁴He nucleus while beta particles are electrons. Hence, the mass of alpha particle is greater than the mass of beta particle. But, the penetrating power is higher in beta particle than alpha particle. Alpha particles can be blocked by few papers but beta particles can go through those papers.

8 0
3 years ago
Read 2 more answers
Which atom has the lowest(smallest) ionization energy?<br> A. Na<br> B.K<br> C. Me<br> D. Ca
serious [3.7K]
K. Ionization energy increases as you go up and to the right, and k is the furthest left and furthest down
7 0
3 years ago
A solution prepared by dissolving 0.100 mole of propionic acid in enough water to make 1.00 L of solution is observed to have a
torisob [31]

Answer:

C) k_a=1.3\times 10^{-5}

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

pH=-log(\sqrt{k_a\times C})

Where, C is the concentration = 0.5 M

Given, pH = 2.94

Moles = 0.100 moles

Volume = 1.00 L

So, Molarity=\frac{Moles}{Volume}=\frac{0.100}{1.00}\ M=0.100\ M

C = 0.100 M

2.94=-log(\sqrt{k_a\times 0.100})

\log _{10}\left(\sqrt{k_a0.1}\right)=-2.94

\sqrt{0.1}\sqrt{k_a}=\frac{1}{10^{2.94}}

k_a=1.3\times 10^{-5}

4 0
3 years ago
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