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Julli [10]
3 years ago
12

If you are given a 1.0 L (1000mL) of an unknown liquid which has the mass of 500 grams it is most likely which of the above subs

tances? Show work to back up your answer. Distilled water density 1.0 g/cm^3 propane density 0.494 g/cm^3 salt water density 1.025 g/cm^3 liquid gold density 17.31g/cm^3
Chemistry
1 answer:
pantera1 [17]3 years ago
6 0
Given in the problem is the mass of the liquid (500 grams) and the volume of the liquid (1000 ml = 1000 cm^3).

We can use these two givens to calculate the density of the liquid using the following rule:
density = mass / volume
density = 500 / 1000 = 0.5 grams / cm^3

Comparing the calculated density with the choices we have, we can deduce that the liquid is most likely to be propane with density 0.494 g / cm^3
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asambeis [7]
248.72 g/mol

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159.62+5(18.02)=249.72 g/mol
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The substance whose lewis structure shows three covalent bonds is
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The substance whose Lewis structure shows three covalent bonds is Nitrogen gas molecule.

<h3>What is Lewis structure?</h3>

Lewis structure is a dot structure which gives idea about the number of valence electrons that are involved in the bonding within the molecule.

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2 years ago
one side of a cube measures 0.53 cm. the mass of the cube is 0.92 g. what is the density of the cube
ziro4ka [17]

Answer:

6.17 g/cm³

Explanation:

Data given:

one side of cube = 0.53 cm

mass of the cube is 0.92 g

density of the cube = ?

Solution:

First we will calculate for volume the cube

As we know all the sides or edges of a cube are equal so volume equation will be

So,

    V = length x width x height

    V = e³

as on side = 0.53 cm

then

     V = (0.53 cm)³

     V = 0.149 cm³

Now we will calculate density of cube

To calculate density, formula will be used

             d = m/v . . . . . (1)

where

d = density

m = mass

v = volume

put values in above formula 1

                   d = 0.92 g / 0.149 cm³

                   d = 6.17 g/cm³

so. the density of cube = 6.17 g/cm³

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3 years ago
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stiks02 [169]

Answer:

the sun

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