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3 years ago

Which expression is equivalent to the given expression? Assume the denominator does not equal zero.

Mathematics

1 answer:

Fudgin [204]3 years ago

4 0

Answer:

$4{J^{9} } {K^{14} }$

Step-by-step explanation:

$\frac{8}{2} \frac{J^{4} }{J^{5} } \frac{K^{8} }{K^{6} }$

$\frac{8}{2}$ = 4

$\frac{J^{4} }{J^{5} }$ = $J^{4+5}$ = $J^{9}$

$\frac{K^{8} }{K^{6} }$ = $K^{8+6}$ = $K^{14}$

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what is the equation of the line that is perpendicular to 5x+6y=16 and passes through the point (-5,7)?

Lapatulllka [165]

Answer:

y=6/5x+13

Step-by-step explanation:

6y=-5x+16

Divide by 6

y=-5/6x + 8/3

Slope: 6/5 (opposite reciprocal)

7=-5(6/5)+b

7=-6+b

b=13

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3 years ago

Which is larger 3/5 or .41

kotegsom [21]

3/5 because it is 0.6 which is bigger than .41

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3 years ago

Read 2 more answers

A 10-foot ladder leans against a wall so that it is 6 feet high at the top. The ladder is moved so that the base of the ladder t

konstantin123 [22]

Answer:

The top of the ladder is now at 10 ft.

Step-by-step explanation:

At the start, we have a height H=6, a length L=10 and a base B, that has to be calculated by the Pythagorean theorem:

$B^2=L^2-H^2=10^2-6^2=100-36=64\\\\B=\sqrt{64}=8$

The base is moved twice the distance the height moves up.

We called this distance x, so we have:

$L^2=(H+x)^2+(B-2x)^2=H^2+2Hx+x^2+B^2-4Bx+4x^2\\\\L^2=(H^2+B^2)+5x^2+(2H-4B)x\\\\L^2=L^2+5x^2+(2H-4B)x\\\\0=5x^2+(2H-4B)x\\\\5x+(2H-4B)=0\\\\x=\dfrac{4B-2H}{5}=\dfrac{4*8-2*6}{5}=\dfrac{32-12}{5}=\dfrac{20}{5}=4$

The new height (H+x) is

$H'=H+x=6+4=10$

The base travels 2x=8, so the new base B' is 0.

This means that the ladder is all against the wall (L=H').

6 0

3 years ago

Plz help its due tonight!!!!

Natalka [10]

Answer:

Domain is (infinity, infinity) so it would hit every single number of x. The range which is y would be greater than or equal to -3. Range starts at -3 and hits every number above that.

8 0

3 years ago

Is the answer true or false?

stira [4]

Answer:

The answer to your question is False

Step-by-step explanation:

Original division

$\frac{3x^{3}+ 5x^{2}- 11}{2x + 1}$

Process

1.- To express a division in a synthetic form we must take the coefficients of the numerator. If there is no coefficient for a variable, we write it as 0.

3x³ + 5x² - 11 = 3 5 0 - 11

The "0" means 0x, this term is not present but we must consider it.

2.- Solve the denominator for x

2x + 1 = 0

2x = -1

x = -1/2

3.- Write the synthetic division

-1/2 3 5 0 -11

4 0

3 years ago