3 years ago

what is the equation of the line that is perpendicular to 5x+6y=16 and passes through the point (-5,7)?

Mathematics

1 answer:

Lapatulllka [165]3 years ago

6 0

Answer:

y=6/5x+13

Step-by-step explanation:

6y=-5x+16

Divide by 6

y=-5/6x + 8/3

Slope: 6/5 (opposite reciprocal)

7=-5(6/5)+b

7=-6+b

b=13

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