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3 years ago

A sea horse riding travels an average of 0.01 miles per hour. At that rate , how fast can a sea horse travel in 2.4 hours?

2 answers:

8 0

2.4 hours* (0.01 miles/ 1 hour)= 0.024 miles/hour.
(Note that the unit cancels out)

The final answer is 0.024 miles/hour~

kondaur [170]3 years ago

5 0

As for this problem, it would be best to approach this with a ratio to ratio approach. This would then involve the equation with fractions which is the common conversion from ratios to easily solve the problems concerning these. The equation then would look somehow like this:

0.01 miles / 1 hour = x miles / 2.4 hours

The easiest way would be just to multiply the numerator, which is the miles, to 2.4. So when it is multiplied to the numerator, the equation then would turn to:

0.01 miles x 2.4 / 1 hour = x miles / 2.4 hours

0.024 miles would be the answer.

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What is 24/53 and 10/21 compared

xz_007 [3.2K]

Answer:

-0.02336028752

Step-by-step explanation:

0.45283018867 -0.47619047619

7 0

3 years ago

Read 2 more answers

Information about a play took up 1/3 of the pages in the program. Information about the actors took up 1/4 of the remaining page

Lisa [10]

Answer:

Step-by-step explanation:

Comment

Let the number of pages = x

Play = 1/3x

Actors = 1/4(x - 1/3 x)

Actors = 1/4(2/3x)

Actors = 2/12 x

Producer Director etc = 2 pages

Equation

Actors = 2 pages

2/12 x = 2

Solution

2x/12 = 2 Multiply both sides by 12

12*2x/12 = 2*12 Combine

2x = 24 Divide by 2

2x/2 = 24/2 Combine

x = 12

Answer

The program had 12 pages.

5 0

2 years ago

Graph x > -1 on the number line

Verdich [7]

Number Line:

Closed Circles are used when signs are "≤" or "≥"

Open Circles are used when signs are "<" or ">"

The graph of x > -1 on a number line would be towards the right from -1 with open circle as the sign is ">"

Graph should look like this:

7 0

2 years ago

The area of the following rectangle is 30 square units. What is the value of x?

Pepsi [2]

Hello!

To find the area of a rectangle you do length * width

You can plug in the values you know

(x - 2) * 5 = 30

Divide both sides by 5

x - 2 = 6

Add 2 to both sides

x = 8

The answer is 8

Hope this helps!

4 0

3 years ago

Read 2 more answers

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago