Answer:
The rocket will hit the floor at 9.57 seconds
Step-by-step explanation:
Given
Take off height = 30ft
Initial velocity= 150ft/s
Required [Missing from the question]
Time to hit the ground
The rocket will hit the ground at:
So, we have:
Rewrite as:
Solve using quadratic formula, we have:
Where:
So, we have:
Split:
Time cannot be negative;
So:
<em>Hence, the rocket will hit the floor at 9.57 seconds</em>
*attachment contains the omitted graph
Answer:
Step-by-step explanation:
The equation that represents the path of the swimmer to the shoreline can be represented in the slope-intercept form, given as .
Where,
Slope (m) = the negative reciprocal of the slope of the shoreline, since it is perpendicular to it = ??
y-intercept (b) = ??
Find the slope of the shoreline using, (0, 1) and (4, 4):
.
Since the slope of the shoreline is ¾. The slope of the path of the swimmer would be the negative reciprocal of ¾.
The negative reciprocal of ¾ = -⁴/3.
The slope of the swimmer's path = -⁴/3.
Using the coordinate of the point of the swimmer (6, 1), and the slope of the path, we can find b, the y-intercept of the path.
Substitute x = 6, y = 1 and m = -⁴/3 into y = mx + b, to find b.
Thus:
1 = (-⁴/3)(6) + b
1 = -8 + b
Add 8 to both sides
1 + 8 = b
9 = b
b = 9
Substitute m = -⁴/3 and b = 9 into y = mx + b.
✅The equation that represents the path would be:
