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Gekata [30.6K]
3 years ago
5

Im Desparate! So Very Desparate xD Please Answer All!

Mathematics
1 answer:
notsponge [240]3 years ago
4 0
2 - b.
3 - a.

I'm not sure about 4. Hope this helps!
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Solve x2+x-1=0 using the quadratic formula.
weeeeeb [17]

Answer:

x = \frac{-1 ±\sqrt{5} }{2}

Step-by-step explanation:

Ignore the A that doesn't belong in the answer

6 0
3 years ago
Please help, this is due tonight
dolphi86 [110]

Answer:

It's B

Step-by-step explanation:

Just divide y by x. For example: 6.6 / 6 = 1.1. This would be B! Hope this helps!

6 0
3 years ago
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What is the effect on the graph of the function f(x) = 2x when f(x) is replaced with f(−
olasank [31]
It would be replaced with f(-2) which is the reciperacle of 2x
4 0
3 years ago
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What is the inverse of f(x) = (5x+2)^2 for x > -2/5
Levart [38]

Answer:

it should be -2/5 or \frac{\sqrt{x} }{5}

Step-by-step explanation:

4 0
3 years ago
Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? ​
bearhunter [10]

Answer:

\sf \log_{10}6=0.7781

Step-by-step explanation:

<u>Given</u>:

\sf \log_{10} 2 = 0.3010

\sf \log_{10} 3 = 0.4771

To find log₁₀ 6, first rewrite 6 as 3 · 2:

\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)

\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay

\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2

Substituting the given values for log₁₀ 3 and log₁₀ 2:

\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}

Therefore:

\sf \log_{10}6=0.7781

Learn more about logarithm laws here:

brainly.com/question/27953288

brainly.com/question/27963321

5 0
1 year ago
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