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lakkis [162]
4 years ago
12

What is 2654 divided by 456

Mathematics
2 answers:
ella [17]4 years ago
7 0
The answer is 5.82017544 i divide the two numbers 2654 and then 456 and got that answer:) hope this helped!!
LenKa [72]4 years ago
6 0
It's 5.82 .. Tasha bff
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A right triangle has a hypotenuse of 70 feet and a leg of 35 feet. What is the length of the other leg? Select one:
saveliy_v [14]
H = 70ft.
P = 35ft.
B = ?

H^2 = P^2 + B^2
70×70 = (35×35) + B^2
B^2 = 4900-1225
B = √3675
B = 35√3 ft.
3 0
3 years ago
The lines below are parallel. If the slope of the solid line is –3, what is the slope of the dashed line?
stepladder [879]

Answer:

-3

Step-by-step explanation:

parallel lines always have the same slope, the y-intercepts will differ

8 0
3 years ago
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe
soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 87, thus \mu = 87.
  • The standard deviation is of 25, thus \sigma = 25.

Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 87}{25}

Z = -1.08

Z = -1.08 has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 87}{25}

Z = 0.92

Z = 0.92 has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 87}{25}

Z = 1.52

Z = 1.52 has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0
3 years ago
Factor each polynomial. Look for a GCF first
weeeeeb [17]

Answer:

20. x\left(x-6\right)\left(x+8\right)

22. 2\left(x+1\right)\left(x+4\right)

24. 5m\left(m-1\right)\left(m+7\right)

Step-by-step explanation:

20. x^3+2x^{2} -48x

The GCF is x, so you group it out of the equation first.

x(x^{2} +2x-48)

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

?+?=2\\?*?=-48

The two numbers would be -6 and 8. You then differentiate the squares.

x\left(x-6\right)\left(x+8\right)

22. 2x^{2} +10x+8

The GCF is 2, so you must group it out.

2(x^{2} +5x+4)

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

?+?=5\\?*?=4

The two numbers would be 1 and 4. Finally, differentiate the squares.

2\left(x+1\right)\left(x+4\right)

24. 5m^{3} +30m^2-35m

The GCF is 5m, so you must group it out.

5m(m^2+6m-7)

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

?+?=6\\?*?=-7

The two numbers would be -1 and 7. Finally, differentiate the squares.

5m\left(m-1\right)\left(m+7\right)

7 0
2 years ago
For the given function, x can have what value?
Lyrx [107]

Answer:

x cannot be -4,-3, or 13

x can be anything else

Step-by-step explanation:

There are infinitely many values x can take where the relation above will be a function.

For it to be a function, you just need to make sure each x is only assigned one y value.

So x couldn't be -4 because it would by assigned to y=2 and y=0.

x couldn't be -3 because it would be assigned to y=1 and y=0.

x couldn't be 13 because it would be assigned to y=5 and y=0.

So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.

5 0
3 years ago
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