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3 years ago

I need help can someone please help me

Mathematics

1 answer:

makkiz [27]3 years ago

7 0

Answer:

The measure of ∠A is 66°.

Step-by-step explanation:

∠A = 3x + 18
∠D = 4x + 2
∠D = ∠A

<u>Now, let's solve the equation. ∠D = ∠A.</u>

=> 3x + 18 = 4x + 2
=> -2 + 18 = x
=> 16 = x

<u>Now, let's substitute the value of x into any equation.</u>

=> 4x + 2
=> 4(16) + 2
=> <u>66°</u>

Hence, the measure of ∠A is 66°.

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3 years ago

Sally’s dance school had 60 students last year. This year there are only 48 students enrolled. By what percent did the enrollmen

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3 years ago

A number, n is multiplied by -5/8 the product is -0.4 how would you set this up to solve

Masja [62]

The value of n in the mathematical statement is 0.64

<h3>How to solve the equation?</h3>

The statement is given as:

n multiplied by -5/8 equals -0.4

Rewrite properly as:

n * -5/8 = -0.4

Multiply both sides by -1

n * 5/8 = 0.4

Multiply both sides by 8/5

n = 0.64

Hence, the value of n in the mathematical statement is 0.64

Read more about mathematical statements at:

brainly.com/question/4344214

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2 years ago

The base of a 40-foot ladder is 8 feet from the wall. How high is the ladder on the wall (round to the nearest foot)?

Luda [366]

Answer:

39 feet.

Step-by-step explanation:

E use the Pythagoras theorem:

40^2 = 8^2 + h^2 as h is the height we require.

h^2 = 1600 - 64

h^2 = 1536

h = 39.19 feet

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3 years ago

Because of the relatively high interest rates, most consumers attempt to pay off their credit card bills promptly. However, this

BigorU [14]

Answer:

a. 0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

b. 0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

c. 0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

d. An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 27 dollars and a standard deviation of 9 dollars.

This means that $\mu = 27, \sigma = 9$

A. What proportion of the bank's Visa cardholders pay more than 29 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 29, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{29 - 27}{9}$

$Z = 0.22$

$Z = 0.22$ has a p-value of 0.5871.

1 - 0.5871 = 0.4129

0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

B. What proportion of the bank's Visa cardholders pay more than 35 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 35, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{35 - 27}{9}$

$Z = 0.89$

$Z = 0.89$ has a p-value of 0.8133.

1 - 0.8133 = 0.1867

0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

C. What proportion of the bank's Visa cardholders pay less than 14 dollars in interest?

This is the p-value of Z when X = 14. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{14 - 27}{9}$

$Z = -1.445$

$Z = -1.445$ has a p-value of 0.0742.

0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

D. What interest payment is exceeded by only 18% of the bank's Visa cardholders?

This is the 100 - 18 = 82nd percentile, which is X when Z has a p-value of 0.82, so X when Z = 0.915.

$Z = \frac{X - \mu}{\sigma}$

$0.915 = \frac{X - 27}{9}$

$X - 27 = 0.915*9$

$X = 35.2$

An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

7 0

3 years ago

￼I need help can someone please help me

I need help can someone please help me