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marin [14]
2 years ago
5

Which protocols are TCP/IP application layer protocols? (choose all that apply)

Computers and Technology
2 answers:
natita [175]2 years ago
5 0

Answer:

Option(b) and Option(c) is the correct answer for the given question.

Explanation:

TCP stands for transmission control protocol, In the TCP protocol firstly it maintains the connection between the sender and the receiver. The receiver always gives an acknowledgment to the sender when it receives the information that's why TCP is reliable protocol it is found in TCP/IP application layer protocols    

UDP stands for user datagram protocol, In the UDP protocol, it does not maintain the connection between the sender and the receiver. The receiver does not give any acknowledgment to the sender that why UDP is not a reliable protocol . it is also found in the TCP/IP application layer protocols

  • In the option(a) IP is found in the network layer that why this option is incorrect.
  • In the option(d) FTP is found in the application layer thats why this option is incorrect .

Hence TCP and UDP are TCP/IP application layer protocols

Arisa [49]2 years ago
5 0

FTP telnet most widely implement of TCP/IP application layer you will work with many others as both a user and a system administrator. Some other commonly used TCP/IP applications are: Domain Name Service (DNS).

Explanation:

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8 0
3 years ago
Read 2 more answers
Question 1
blondinia [14]

Answer:

888 + 88 + 8 + 8 + 8 = 1000

Explanation:

Required

Add up to 1000 using only digit 8

There is no straight way to answer this question; so, we make use of trial by error method to arrive at our solution.

After several trials, I found out that:

888 + 88 + 8 + 8 + 8 = 1000

6 0
2 years ago
Class members are accessed via the ____(1)_____ operator in conjunction with the name of an object of the class, or via the ___(
Alborosie

Answer:

1.ClassName and . operator

2. ClassName and [] operator

Explanation:

There are two ways to get the members of a class first one is by using dot(.) operator.

Example : with assumption that person is a class object and age is the member in it we can use it as:

person.age

Second way is to use [] operator with member as a string in it which is used by the compiler as key to get its value.

Example : person["age"]

5 0
3 years ago
Objects of the calculator class require no additional information when created. define an object named calc, of type calculator.
Grace [21]

Answer

calculator calc;

Explanation

An object is an instance of a class. And a class is what defines or describes the behavior or the state of the object of its type. When a class is defined no memory is allocated until when an object is created memory is allocated.

4 0
3 years ago
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For this exercise, we are going to take a look at an alternate Calculator class, but this one is broken. There are several scope
vekshin1

Answer:

public class Calculator {

   private int total;

   private int value;

   

   public Calculator(int startingValue){

       // no need to create a new total variable here, we need to set to the our instance total variable

       total = startingValue;

       value = 0;

   }

   public int add(int value){

       //same here, no need to create a new total variable. We need to add the value to the instance total variable

       total = total + value;

       return total;

   }

   /**

   * Adds the instance variable value to the total

   */

   public int add(){

       // no need to create a new total variable. We need to add the value to the instance total variable

       total += value;

       return total;

   }

   public int multiple(int value){

       // no need to create a new total variable. We need to multiply the instance total variable by value.

       total *= value;

       return total;

   }

   //We need to specify which value refers to which variable. Otherwise, there will be confusion. Since you declare the parameter as value, you need to put this keyword before the instance variable so that it will be distinguishable by the compiler.

   public void setValue(int value){

       this.value = value;

   }

   public int getValue(){

       return value;

   }

}

Explanation:

I fixed the errors. You may see them as comments in the code

7 0
3 years ago
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